Python requests csrf token

POST Запрос CSRF в python?

Пробую пройти авторизацию на ресурсе.
Для этого требуется получитьь CSRF или cookies.
Получаю CSRF и отрпавляю POST запрос но в ответ приходит «CSRF verification failed»
Как в request подставить ранее полученые cookies?

import requests from bs4 import BeautifulSoup from lxml import html import time import re source = ['https://chatur', 'bate.com','/auth/login/'] #print(source[0]+source[1]) xead = source[0]+source[1] xeads = source[0]+source[1]+source[2] headers = < 'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8', 'Accept-Encoding': 'gzip, deflate', 'Origin': f'', 'Referer': f'', 'Upgrade-Insecure-Requests': '1', 'Content-Type': 'application/json', 'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.102 Safari/537.36' > with requests.Session() as s: url = f'' r = s.get(url, headers=headers) tree = html.fromstring(r.content) csrf = tree.xpath('//*[@id="main"]/div/div/form/input/@value') print(csrf[1]) ksrf = r.headers.get('Set-Cookie') result = re.findall(r'csrftoken=\w+', ksrf) results = re.findall(r'\w+', str(result)) print(csrf[1], results[1]) login_data = < 'next': None, 'csrfmiddlewaretoken': csrf[1], 'username': 'thorix0', 'password': 'Lovacska00' >cfduid = (r.cookies.get('__cfduid')) affkey = (r.cookies.get('affkey')) csrftoken = (r.cookies.get('csrftoken')) dwf_s_a = (r.cookies.get('dwf_s_a')) sbr = (r.cookies.get('sbr')) headers = < 'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8', 'Accept-Encoding': 'gzip, deflate', 'Origin': f'', 'Referer': f'', 'cookie': f'__cfduid=; csrftoken=; affkey=; sbr=; dwf_s_a=; xaduuid=46286a6b-b343-4de1-8bf3-642063c76746; _ga=GA1.2.1099840177.1589195089; _gid=GA1.2.220136171.1589195089; agreeterms=1; stcki="VbMkPs=0"; __utfpp="f:trnx9dd2486c9fa7ae89556a1dbfe9069386:1jYcch:s1GBrAZDOlTSXBaA_JGaB2j5mOw"; __cf_bm=099f0bcce6e7f825e6cdb0255872df4af896b74f-1589321255-1800-AX9QQ3hj3q9ixK08V17u0v2XzC87BMlnVdE2FOthWmdCvYoGQG+KrjSL9Ra19JcnrwjKrwtQevQpW2azIgatD0A=', 'Upgrade-Insecure-Requests': '1', 'Content-Type': 'application/json', 'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/70.0.3538.102 Safari/537.36' > """print(r.cookies.get('__cfduid')) print(r.cookies.get('affkey')) print(r.cookies.get('csrftoken')) print(r.cookies.get('dwf_s_a')) print(r.cookies.get('sbr')) """ print(r.cookies) time.sleep(5) #login_data['form_build_id'] = soup.find('input', attrs=)['value'] rr = s.post(url, data=login_data, headers=headers, cookies=r.cookies) print(rr.content)

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How to get x-csrf-token in python

It can come with response headers, in that case getting it is easy. ,It can be inside of a script tag with JavaScript code. Getting it will be tricky. But, you can always use regex to isolate it.,Sometimes page meta holds the CSRF token. You have to parse the html content of the page to get it. Find the proper CSS selector for it. See an example: ,There are a few possible locations of the CSRF token. Different websites use different ways to pass it to browser. Here are some of them:

See the following code example. You can use it directly to login into a website that only uses cookies to store login information.

import requests LOGIN_URL = 'https://examplenotarealpage.com' headers = < 'accept': 'text/html,application/xhtml+xml,application/xml', 'user-agent': 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36' >response = requests.get(LOGIN_URL, headers=headers, verify=False) headers['cookie'] = '; '.join([x.name + '=' + x.value for x in response.cookies]) headers['content-type'] = 'application/x-www-form-urlencoded' payload = < 'username': 'user_name', 'password': 'randompass123' >response = requests.post(LOGIN_URL, data=payload, headers=headers, verify=False) headers['cookie'] = '; '.join([x.name + '=' + x.value for x in response.cookies]) 

Sometimes page meta holds the CSRF token. You have to parse the html content of the page to get it. Find the proper CSS selector for it. See an example:

from bs4 import BeautifulSoup soup = BeautifulSoup(response.text, 'lxml') csrf_token = soup.select_one('meta[name="csrf-token"]')['content'] 

Answer by Ishaan Preston

Refactoring several attribute fields at the same time , @MartijnPieters yes CSRF verification failed. Request aborted. – Jeff Nov 26 ’12 at 15:12 ,Similarly, using django’s csrf_client note the primary difference is using csrftoken.value in the login_data. Tested with Django 1.10.5 —,Making statements based on opinion; back them up with references or personal experience.

If you are going to set the referrer header, then for that specific site you need to set the referrer to the same URL as the login page:

import sys import requests URL = 'https://portal.bitcasa.com/login' client = requests.session() # Retrieve the CSRF token first client.get(URL) # sets cookie if 'csrftoken' in client.cookies: # Django 1.6 and up csrftoken = client.cookies['csrftoken'] else: # older versions csrftoken = client.cookies['csrf'] login_data = dict(username=EMAIL, password=PASSWORD, csrfmiddlewaretoken=csrftoken, next='/') r = client.post(URL, data=login_data, headers=dict(Referer=URL)) 

Answer by Cassidy Coffey

In any template that uses a POST form, use the csrf_token tag inside the element if the form is for an internal URL, e.g. The first defense against CSRF attacks is to ensure that GET requests (and other ‘safe’ methods, as defined by RFC 7231#section-4.2.1) are side effect free. Requests via ‘unsafe’ methods, such as POST, PUT, and DELETE, can then be protected by following the steps below.,A page makes a POST request via AJAX, and the page does not have an HTML form with a csrf_token that would cause the required CSRF cookie to be sent.,This ensures that only forms that have originated from trusted domains can be used to POST data back.

Answer by Santiago Buckley

No Comments on Get and pass CSRF token using python requests library , Random Forest vs Gradient boosting ,Sequentum Enterprise review, Bagging and Random Forest

import sys import requests URL = 'https://portal.bitcasa.com/login' client = requests.session() # Retrieve the CSRF token first client.get(URL) # sets cookie if 'csrftoken' in client.cookies: # Django 1.6 and up csrftoken = client.cookies['csrftoken'] else: # older versions csrftoken = client.cookies['csrf'] # Pass CSRF token both in login parameters (csrfmiddlewaretoken) # and in the session cookies (csrf in client.cookies) login_data = dict(username=EMAIL, password=PASSWORD, csrfmiddlewaretoken=csrftoken, next='/') r = client.post(URL, data=login_data, headers=dict(Referer=URL))

Answer by Rodney Brock

Let’s assume you use the python library Requests,You need to use the method set which accepts key value parameters:,The create action executes the HTTP method POST which is usually protected by CSRF and therefore you must make some effort to initialize your HTTP Session to send POST requests acceptable by the remote server.

import pyodata import requests SERVICE_URL = 'http://example.io/TheServiceRoot/' session = requests.Session() response = session.head(SERVICE_URL, headers=) token = response.headers.get('x-csrf-token', '') session.headers.update() theservice = pyodata.Client(SERVICE_URL, session) 

Answer by Issac Jacobs

How do you pass a csrftoken with the python module Requests? This is what I have but it’s not working, and I’m not sure which parameter to pass it into (data, headers, auth. ),Passing csrftoken with python Requests ,If you are going to set the referrer header, then for that specific site you need to set the referrer to the same URL as the login page:,When using unsecured http, the Referer header is often filtered out and otherwise easily spoofable anyway, so most sites no longer require the header to be set. However, when using an SSL connection and if it is set, it does make sense for the site to validate that it at least references something that could logically have initiated the request. Django does this when the connection is encrypted (uses https://), and actively requires it then.

How do you pass a csrftoken with the python module Requests? This is what I have but it’s not working, and I’m not sure which parameter to pass it into (data, headers, auth. )

import requests from bs4 import BeautifulSoup URL = 'https://portal.bitcasa.com/login' client = requests.session(config=) # Retrieve the CSRF token first soup = BeautifulSoup(client.get('https://portal.bitcasa.com/login').content) csrftoken = soup.find('input', dict(name='csrfmiddlewaretoken'))['value'] login_data = dict(username=EMAIL, password=PASSWORD, csrfmiddlewaretoken=csrftoken) r = client.post(URL, data=login_data, headers=) 

Same error message every time.

Forbidden (403)
 
CSRF verification failed. Request aborted.
 

Answer by Ezequiel Payne

The token will be expected to be present in the body of any POST request with the name “csrf_token”. Alternatively you can pass it via a header called “X_CSRF_Token”. This allows for sending the token in AJAX requests:,Once we have the ability to use a session to persist a CSRF token, we can secure our journal app against this type of attack. If we wanted to, we could manually construct individual views to require a CSRF token:,If the manual check fails, then an HTTPBadRequest exception is raised.,When testing views, you may need to handle CSRF-protected views a bit differently.

 
Amount: To Account: Savings Account Checking Account  
 

Answer by Keanu Skinner

You have to fetch the csrf token from Django’s csrf_token cookie. But this will be set only if the CSRF middleware is enabled in Django. ,There! You’ve been able to include Django’s csrf_token in React. ,ensure_csrf_cookie(views): This enforces a view to set a CSRF cookie, even if the csrf_token template tag isn’t used. ,You can then create a global csrftoken.js file that has the following:

Answer by Veda Hardin

Django offers middleware for protecting a web server against CSRF attacks. To protect your apps, the middleware must be activated in your project. Also, you have to include the csrf_token tag inside the form elements which point to any in-project URLs.,Protect your application against CSRFMenu Toggle,Try transmitting the token to the client within a hidden HTML form field, using the POST method. This way the token will be included as a request parameter when the form is submitted:,In order to protect a React application against CSRF, you have to introduce a security solution in your app, and have the web server support it.

For example, a CSRF token in PHP can be generated as follows:

$_SESSION[‘token’] = bin2hex(random_bytes(24));

Источник

Python requests csrf token

Get and pass CSRF token using python requests library

import sys import requests URL = 'https://portal.bitcasa.com/login' client = requests.session() # Retrieve the CSRF token first client.get(URL) # sets cookie if 'csrftoken' in client.cookies: # Django 1.6 and up csrftoken = client.cookies['csrftoken'] else: # older versions csrftoken = client.cookies['csrf'] # Pass CSRF token both in login parameters (csrfmiddlewaretoken) # and in the session cookies (csrf in client.cookies) login_data = dict(username=EMAIL, password=PASSWORD, csrfmiddlewaretoken=csrftoken, next='/') r = client.post(URL, data=login_data, headers=dict(Referer=URL))

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Get CSRF token using python requests

See the following code example. You can use it directly to login into a website that only uses cookies to store login information.

import requests LOGIN_URL = 'https://examplenotarealpage.com' headers = < 'accept': 'text/html,application/xhtml+xml,application/xml', 'user-agent': 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/67.0.3396.99 Safari/537.36' >response = requests.get(LOGIN_URL, headers=headers, verify=False) headers['cookie'] = '; '.join([x.name + '=' + x.value for x in response.cookies]) headers['content-type'] = 'application/x-www-form-urlencoded' payload = < 'username': 'user_name', 'password': 'randompass123' >response = requests.post(LOGIN_URL, data=payload, headers=headers, verify=False) headers['cookie'] = '; '.join([x.name + '=' + x.value for x in response.cookies]) 

There are a few possible locations of the CSRF token. Different websites use different ways to pass it to browser. Here are some of them:

• It can come with response headers, in that case getting it is easy.
• Sometimes page meta holds the CSRF token. You have to parse the html content of the page to get it. Find the proper CSS selector for it. See an example:

from bs4 import BeautifulSoup soup = BeautifulSoup(response.text, 'lxml') csrf_token = soup.select_one('meta[name="csrf-token"]')['content'] 

Solution 2

import requests from bs4 import BeautifulSoup headers = login_data = < 'name' : 'USERNAME', 'pass' : 'PASSWORD', 'form_id':'new_login_form', 'op':'login' >with requests.Session() as s: url = 'https://www.codechef.com/' r = s.get(url,headers=headers,verify=False) #print(r.content) # to find name of csrftoken and form_build_id soup = BeautifulSoup(r.text, 'lxml') csrfToken = soup.find('input',attrs = )['value'] form_build_id = soup.find('input',attrs = ) ['value'] login_data['csrfToken'] = csrfToken login_data['form_build_id'] = form_build_id r = s.post(url,data=login_data,headers = headers) print(r.content) 

You can directly use this but their are few things to change:
1.check your user-agent in your browser network option
2.check your name attribute for csrf-token and form_build_id by print(r.content) and find csrftoken and form-build-id and check their name attribute.

final step :

search logout in your r.content if it is their then you are login.

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