pip install returning invalid syntax
I’ve just installed python 3.6 which comes with pip However, in Windows command prompt, when I do: ‘pip install bs4’ it returns ‘SyntaxError: invalid syntax’ under the install word. Typing ‘python’ returns the version, which means it is installed correctly. What could be the problem?
18 Answers 18
-m module-name Searches sys.path for the named module and runs the corresponding .py file as a script.
Sometimes the OS can’t find pip so python or py -m may solve the problem because it is python itself searching for pip .
Code-only answers are not terribly helpful. Please consider explaining what this code does, how it solves the OP’s problem.
You need to be in the specific folder where pip.exe exists, then do the following steps:
cd C:\Users\username\AppData\Local\Programs\Python\Python37-32\Scripts Don’t enter in the python shall, Install in the command directory.
Not inside the python pip cannot be installed inside the python.
Even in the version 3.+ you don’t have to write the python 3 instead just python.
python -m pip install --upgrade pip python -m pip install jupyter Try running cmd as administrator (in the menu that pops up after right-clicking) and/or entering «pip» alone and then
«D:\Program Files\Py\Scripts\pip.exe» install numpy -U
YOUR PATH to pip.exe in Python folder + install + YOUR LIB + -U
The OS is not recognizing ‘python’ command. So try ‘py’
The problem is the OS can’t find Pip. Pip helps you install packages MODIFIED SOME GREAT ANSWERS TO BE BETTER
Method 1 Go to path of python, then search for pip
E.g
cd C:\Users\Username\AppData\Local\Programs\Python\Python37-32
In this directory, search pip with python -m pip then install package
E.g
python -m pip install ipywidgets
-m module-name Searches sys.path for the named module and runs the corresponding .py file as a script.
OR
GO TO scripts from CMD. This is where Pip stays 🙂
cd C:\Users\User name\AppData\Local\Programs\Python\Python37-32\Scripts>
pip install anypackage
Invalid Syntax error when running python from inside Visual Studio Code
In the following screenshot you can see the command i use to run the file and also which python extension i use. But running the file from within my terminal with python3 test.py works just fine. Does anyone know what the problem is when running it from within VS Code?
I believe something may be funky with the Python interpreter settings/path in VSC. Can you confirm these?
my terminal uses /usr/local/bin/python3 and vs code uses /usr/local/opt/python/bin/python3.7. But when i use the path vs code uses as command in my terminal it works as well
Well, VSC tries to execute the line /usr/local/opt/python/bin/python3.7 /../test.py in the python interactive shell which is obviously wrong. Not sure what’s up with that.
Just make this thread clear: If you are stacked in Python interpreter (case when you have in terminal «>>») enter/write «exit()», «quit()», or select «Ctrl-Z«
10 Answers 10
Think this is a bug of VS Code.
When you use «run selection/line in python terminal» command, VS Code starts python interpreter and doesn`t quit it after completion.
You should use exit() command in python interpreter window to end python session.
After that «run python file in terminal» will work fine.
Looks like this is a bug in VS Code.
When i create a new file, assign python language to it and then save it then it works when i run the python file from within the editor.
But when i create a new file, assign python langauge but dont save it, execute «Run Selection/Line in Python Terminal» afterwards save it and then run «Run Python file in Terminal» it doen’t work. So this seems to be an VS Code related issue.
Yep, a restart is required for pylint to work properly after installation. I had the same problem with false error messages before.
The problem for me was that I accidentally used Shift + Return which executed the python program, when in fact I meant to hit CTRL + Return to move to the next line without touching the mouse.
Using exit() command in the console worked.
It’s a probable bug in VS code. I don’t know why there hasn’t been a patch for this. After typing exit() in the terminal, the rerun should work fine. You could also try Ctrl+F5 to run in a debug mode.
Disable terminal.integrated.inheritEnv in settings. This was suggested by VSCode for me and it worked.
Yeap, worked for me too. I confidently ignored this suggestion from VSCode earlier. Now, I am here having that ahhh. moment.
I got the same issue, simply restart the Vs-Code it works for me !!
I experienced this issue when attempting to change my default terminal settings. I continually ran into a situation where the «Run Python File in Terminal» command would result in syntax errors while the «Run Selection/Line in Python Terminal» command would error but still display the results. Irritating to say the least.
Here’s the settings I utilized to resolve the syntax errors issue.
Note: Enabling Pylint did not resolve my issue, in fact it continued to pop-up even after selecting to enable it. These specific user/workspace/folder settings resolved that issue for me too.
Note: Since the terminal defaults to Powershell, you have to type Python to enter manual commands directly into the python terminal and exit() to close it to allow the python file to run properly again.
USER SETTINGS
WORKSPACE SETTINGS
FOLDER SETTINGS
"python.linting.pylintEnabled": true, "python.pythonPath": "C:\\Python3.7.2\\python.exe", How to resolve file «», line 1 syntaxerror: invalid syntax?
I’m a beginner in Python. I tried to resolve this error but I couldn’t. This code worked before but not anymore. I run the code in PyCharm and getting this error:
Traceback (most recent call last): File "C:/Users/MJavad/Desktop/test.py", line 3, in b = float(sys.argv[1]) IndexError: list index out of range File "", line 1 python test.py 1 2 ^ SyntaxError: invalid syntax import sys import math b = float(sys.argv[1]) c = float(sys.argv[2]) f = b * b - 4.0 * c d = math.sqrt(f) print((-b + d) / 2.0) print((-b - d) / 2.0) 
and this is the code and error in PyCharm:
Please repeat the intro tour, especially MRE. We need the context of your command line that will allow us to reproduce your problem. Your error message is from the command-line interpreter, not Python.
1 Answer 1
It seems that there is confusion about how Python code can be executed and processed.
- On the one hand, there is the Python interpreter in the interactive mode. This is usually started with the command python (without arguments) and then you have the possibility to execute Python code directly in an interactive Python specific shell. This distinguishes Python from other languages that need to be compiled first to execute code. Further information are available in the official Python tutorial.
- On the other hand, Python can also be executed in such a way that not the interpreter with an interactive shell is started, but a file is read and processed. This is usually done with the command python together with the path to the Python file as argument, e.g. python test.py . See also the documentation about using Python.
With this knowledge the problems that have happened to you can now be explained and solved:
If you are simply starting the Python interpreter in interactive mode (without any further arguments), you don’t have access to the command line arguments any more, for example:
$ python3.8 # or whatever your command is, maybe only python or python3 Python 3.8.0 (default, Oct 28 2019, 16:14:01) [GCC 8.3.0] on linux Type "help", "copyright", "credits" or "license" for more information. >>> import sys; sys.argv [''] As you can see, there isn’t really a usable information in argv . And that is your problem: The arguments aren’t successfully loaded into sys.argv . So an index error happened, because the arguments are simply missing:
$ python3.8 Python 3.8.0 (default, Oct 28 2019, 16:14:01) [GCC 8.3.0] on linux Type "help", "copyright", "credits" or "license" for more information. >>> import sys >>> sys.argv[1] Traceback (most recent call last): File "", line 1, in IndexError: list index out of range The only difference to your example is that you have already provided the path to the script, because it’s File «C:/Users/MJavad/Desktop/test.py», line 3, in instead of File «», line 1, in . So you have started the program via python test.py , but also without any further arguments which would be loaded into sys.argv in the program, see:
$ python3.8 test.py Traceback (most recent call last): File "test.py", line 3, in b = float(sys.argv[1]) IndexError: list index out of range Your sys.argv now looks like this: [‘test.py’] , but still no index positions 1 and 2 available. So you have to invoke python also with additional arguments which will be passed into sys.argv :
$ python3.8 test.py 1 2 Traceback (most recent call last): File "test.py", line 6, in d = math.sqrt(f) ValueError: math domain error And it worked! Ok, you have another exception, but it’s in line 6 and every line before was successfully processed, also the command line arguments. Now you can proceed to debug your program, i.e. start programming or trying other parameters than 1 and 2 etc.
So that’s the theory. Since you’re also using PyCharm and have the «Terminal», the «Run configuration» and a «Python Console» available, things get a bit more complicated:
- The «Terminal» should have a prompt available if you start one. This prompt shouldn’t be a prompt from the Python interpreter (normally prefixed by >>> ). It should be a terminal prompt (normally prefixed by an $ at the end), where you can also start a python interpreter in interactive mode or start a python program as described above. This «Terminal» is a terminal emulator given you by PyCharm and can also do other things for you, not only starting python programs. See the PyCharm documentation for more information.
- The «Python Console» is a similar Python interpreter you also can get if starting python from the «Terminal». But then, you already started the interactive mode of the interpreter and there are no possibilities to pass command line arguments (maybe somewhere, but not as default). See the PyCharm documentation for more information.
- If you’re using an IDE like PyCharm, you should normally start the program as recommended by the IDE. In this case, you’re writing a file and start the file neither by running the «Terminal», nor going into an interactive Python shell. Instead of this, you have to configure the IDE «Run» as described in the PyCharm documentation or as you can see here: This is just the GUI way of calling python C:/Users/MJavad/Desktop/test.py 1 2 directly inside PyCharm.
So I would recommend that you’re only starting your programs via option 3 (via «Run» configuration or «DEBUG» configuration). You only have to pay attention, running the right configuration (see if the path is the correct one and the parameters are right).
It is not normal to have a Python prompt ( >>> ) directly after starting a «Terminal», though. And inside interactive mode of Python’s interpreter, you simply cannot start a python script, because you’re already in a python interpreter, for example:
$ python3.8 Python 3.8.0 (default, Oct 28 2019, 16:14:01) [GCC 8.3.0] on linux Type "help", "copyright", "credits" or "license" for more information. >>> python test.py 1 2 File "", line 1 python test.py 1 2 ^ SyntaxError: invalid syntax I should also mention that you can pass arguments into python interactive mode, for example (the — stands for ):
$ python3.8 - hello world Python 3.8.0 (default, Oct 28 2019, 16:14:01) [GCC 8.3.0] on linux Type "help", "copyright", "credits" or "license" for more information. >>> import sys; sys.argv ['-', 'hello', 'world'] >>>