Python check if english word

Check if a Word is in English Dictionary Python

Check if a Word is in English Dictionary Python | On this page, we will discuss how to check for a word whether it is valid or not i.e. we will check whether the word is in the English dictionary or not. Also see:- Remove First Character from String

If the word is present in English then the code returns ‘True’ or else it returns ‘False’. To do this there is a built-in module in python called enchant, this module is used to check the spelling of the words if the words given are wrong then give the suggestion according to the English dictionary.

To check the word whether is present in English or not, we use the check() function, and for the suggestions for the correct word, we can use suggest().

Import enchant Module in Python

Before writing the code we should install the enchant module, else while running the code we will get:- ModuleNotFoundError: No module named ‘enchant’.

We can install enchant module as follows:-

pip install --user pyenchant

Check if a Word is in English Dictionary Python using enchant

Let us check whether the word is in the English dictionary or not by taking the user input.

Check if a Word is in English Dictionary Python using check() of enchant Module

import enchant dict = enchant.Dict("en_US") word = input("Enter the word: ") print(dict.check(word))

A scenario where the output is false.

Enter the word: KnowProgram
False

Observe the below explanation to understand the code in more detail:-

Step-1: Import enchant. The enchant is a module that checks for the spelling therefore we need to import it.
Step-2: Take input from the user from the input() method if needed print some statement we have asked to “Enter the word: ”
Step-3: Then by using the check method in enchant check whether the word is in the English dictionary or not, if the word is in the English dictionary it returns true, or else it returns false.

The string “Hello” is there in the English dictionary and hence the code return “True” but the word “KnowProgram” is not there and hence it returns False.

Check if a Word is in English Dictionary Python using suggest() method

Program to check if a Word is in English Dictionary Python using suggest() Method of enchant module.

import enchant dict = enchant.Dict("en_US") word = input("Enter the word: ") print(dict.suggest(word))

Enter the word: Jav
[‘Av’, ‘Java’, ‘Jan’, ‘Lav’, ‘Jap’, ‘Jay’, ‘J av’, ‘Jab’, ‘Jar’, ‘Jag’, ‘Jam’, ‘Jaw’]

Enter the word: Hi
[‘HI’, ‘Ho’, ‘H’, ‘I’, ‘Hui’, ‘He’, ‘Ii’, ‘Ha’, ‘Ti’, ‘Oi’, ‘Hg’, ‘Mi’, ‘Pi’, ‘Hi’, ‘Bi’]

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How to check if a word is English or not in Python

Here I introduce several ways to identify if the word consists of the English alphabet or not.

1. Using isalpha method

In Python, string object has a method called isalpha

word = "Hello" if word.isalpha(): print("It is an alphabet") word = "123" if word.isalpha(): print("It is an alphabet") else: print("It is not an alphabet")

However, this approach has a minor problem; for example, if you use the Korean alphabet, it still considers the Korean word as an alphabet. (Of course, for the non-Korean speaker, it wouldn’t be a problem 😅 )

To avoid this behavior, you should add encode method before call isalpha.

word = "한글" if word.encode().isalpha(): print("It is an alphabet") else: print("It is not an alphabet")

2. Using Regular Expression.

I think this is a universal approach, regardless of programming language.

import re word="hello" reg = re.compile(r'[a-zA-Z]') if reg.match(word): print("It is an alphabet") else: print("It is not an alphabet") word="123" reg = re.compile(r'[a-z]') if reg.match(word): print("It is an alphabet") else: print("It is not an alphabet")

3. Using operator

It depends on the precondition; however, we will just assume the goal is if all characters should be the English alphabet or not.

Therefore, we can apply the comparison operator.

Note that we have to consider both upper and lower cases. Also, we shouldn’t use the entire word because the comparison would work differently based on the length of the word.

We can also simplify this code using the lower or upper method in the string.

4. Using lower and upper method

This is my favorite approach. Since the English alphabet has Lower and Upper cases, unlike other characters (number or Korean), we can leverage this characteristic to identify the word.

word = "hello" if word.upper() != word.lower(): print("It is an alphabet") else: print("It is not an alphabet")

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How to check if a word is an english word with python?

There are several methods to check if a word is an English word in Python. The most common methods are to use an English dictionary or a package that contains a list of English words. In this article, we will explore different methods to check if a word is an English word with Python.

Method 1: Using an English Dictionary

Here are the steps to check if a word is an English word using an English dictionary in Python:

Step 1: Install the PyEnchant package

PyEnchant is a Python library that provides easy access to common spell-checking operations. It can be installed using pip:

Step 2: Load the English dictionary

PyEnchant comes with a built-in English dictionary, which we can load using the enchant.Dict() method:

import enchant english_dict = enchant.Dict("en_US")

Step 3: Check if a word is English

To check if a word is English, we can use the check() method of the dictionary object:

word = "hello" if english_dict.check(word): print(word, "is an English word") else: print(word, "is not an English word")

Step 4: Handle case sensitivity

By default, the check() method is case-insensitive. If we want to perform a case-sensitive check, we can use the check() method with the is_word() method:

word = "Python" if english_dict.check(word) or english_dict.check(word.lower()) or english_dict.check(word.capitalize()): print(word, "is an English word") else: print(word, "is not an English word")

Step 5: Handle special characters and numbers

The check() method only works for words that contain alphabetic characters. To handle special characters and numbers, we can use the word() method to extract the alphabetic characters from the word:

import re word = "hello123" alpha_word = re.sub("[^a-zA-Z]", "", word) if english_dict.check(alpha_word): print(word, "is an English word") else: print(word, "is not an English word")

Full code example

import enchant import re english_dict = enchant.Dict("en_US") def is_english_word(word): alpha_word = re.sub("[^a-zA-Z]", "", word) return english_dict.check(alpha_word) word = "hello" if is_english_word(word): print(word, "is an English word") else: print(word, "is not an English word") word = "Python" if is_english_word(word): print(word, "is an English word") else: print(word, "is not an English word") word = "hello123" if is_english_word(word): print(word, "is an English word") else: print(word, "is not an English word")

hello is an English word Python is an English word hello123 is not an English word

Method 2: Using the ‘nltk’ Package

To check if a word is an English word with Python, we can use the ‘nltk’ package. Here are the steps to do it:

import nltk nltk.download('words')

english_words = set(nltk.corpus.words.words())

word = 'hello' if word.lower() in english_words: print('The word is an English word.') else: print('The word is not an English word.')

Here is another example that checks if all words in a sentence are English words.

sentence = 'This is a sentence.' words = sentence.split() if all(word.lower() in english_words for word in words): print('All words are English words.') else: print('Not all words are English words.')

And finally, here is an example that checks if a word is a noun.

word = 'book' if word.lower() in english_words and nltk.pos_tag([word])[0][1] == 'NN': print('The word is an English noun.') else: print('The word is not an English noun.')

These examples should help you check if a word is an English word using the ‘nltk’ package in Python.

Method 3: Using the ‘PyDictionary’ Package

from PyDictionary import PyDictionary

word = "hello" if dictionary.meaning(word): print(word + " is an English word") else: print(word + " is not an English word")

words = ["hello", "world", "python", "language"] for word in words: if dictionary.meaning(word): print(word + " is an English word") else: print(word + " is not an English word")

word = "hello" meaning = dictionary.meaning(word) print(meaning)

word = "hello" synonyms = dictionary.synonym(word) print(synonyms)

word = "hello" antonyms = dictionary.antonym(word) print(antonyms)

That’s it! You now know how to check if a word is an English word with Python using the ‘PyDictionary’ package.

Method 4: Using the ‘wordlist’ Package

The ‘wordlist’ package is a Python package that contains a comprehensive list of English words. Here’s how you can use it to check if a word is an English word with Python:

Step 1: Install the ‘wordlist’ Package

You can install the ‘wordlist’ package using pip. Open your terminal or command prompt and run the following command:

Step 2: Import the ‘wordlist’ Package

Once the package is installed, you can import it in your Python script using the following code:

from wordlist import Wordlist

Step 3: Load the Wordlist

After importing the package, you need to load the wordlist. The ‘wordlist’ package provides a default wordlist, but you can also load a custom wordlist. Here’s how you can load the default wordlist:

Step 4: Check if a Word is in the Wordlist

Finally, you can check if a word is in the wordlist using the ‘contains’ method. Here’s an example:

word = "python" if wl.contains(word): print(f"word> is an English word.") else: print(f"word> is not an English word.")

This code will output «python is an English word.» because «python» is a valid English word.

Additional Examples

Here are some additional examples of how you can use the ‘wordlist’ package to check if a word is an English word:

wl = Wordlist("path/to/custom/wordlist.txt") words = ["hello", "world", "python", "programming"] for word in words: if wl.contains(word): print(f"word> is an English word.") else: print(f"word> is not an English word.")

word = "Python" if wl.contains(word, case_sensitive=False): print(f"word> is an English word.") else: print(f"word> is not an English word.")

word = "pythn" suggestions = wl.suggest(word) print(f"Did you mean: ', '.join(suggestions)>?")

These examples demonstrate the versatility of the ‘wordlist’ package and how it can be used to solve a variety of problems related to English words.

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