Питон syntaxerror break outside loop

Что означает ошибка SyntaxError: ‘break’ outside loop

Ситуация: мы пишем опросник на Python, и нам важно, чтобы его мог пройти только совершеннолетний. Для этого мы добавляем в код такую логику:

1. Спрашиваем про возраст.
2. Смотрим, он больше 18 или нет.
3. Если нет — останавливаем программу.
4. Пишем дальше код, который будет работать, если участнику есть 18 лет и программа не остановилась.

На Python это выглядит так:

# запрашиваем возраст age_txt = input('Введите свой возраст: ') # переводим введённое значение в число age = int(age_txt) # если меньше 18 лет if age < 18: # выводим сообщение print('Вы не можете участвовать в опросе') # выходим из программы break # спрашиваем имя name_txt = input('Как вас зовут: ')

Вроде всё логично, но после запуска мы получаем ошибку:

❌ SyntaxError: 'break' outside loop

Что это значит: в отличие от многих других языков, команда break в Python используется только для выхода из цикла, а не выхода из программы в целом.

Когда встречается: когда мы хотим выйти из программы в середине её работы, но не знаем как.

Что делать с ошибкой SyntaxError: 'break' outside loop

Всё зависит от того, что вы хотите сделать.

Если вы хотите выйти из цикла, то break служит как раз для этого — нужно только убедиться, что всё в порядке с отступами. Например, здесь мы выйдем из цикла, как только переменная станет больше 9:

for i in range(10): print(i) if i > 8: break

А если вы хотите закончить работу программы в произвольном месте, то нужно вместо break использовать команду exit() . Она штатно завершит все процессы в коде и остановит программу. Это как раз подойдёт для нашего примера с опросником — теперь программа остановится, если возраст будет меньше 18:

# запрашиваем возраст age_txt = input('Введите свой возраст: ') # переводим введённое значение в число age = int(age_txt) # если меньше 18 лет if age < 18: # выводим сообщение print('Вы не можете участвовать в опросе') # выходим из программы exit() # спрашиваем имя name_txt = input('Как вас зовут: ')

В «Яндекс Практикуме» можно стать разработчиком, тестировщиком, аналитиком и менеджером цифровых продуктов. Первая часть обучения всегда бесплатная, чтобы попробовать и найти то, что вам по душе. Дальше — программы трудоустройства.

Управляем базой данных из командной строки

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Сохраняем тему и добавляем переключатель

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Питон syntaxerror break outside loop

Last updated: Feb 17, 2023
Reading time · 3 min

# SyntaxError: 'break' outside loop in Python

The Python "SyntaxError: 'break' outside loop" occurs when we use the break statement outside of a loop.

To solve the error, use a return statement to return a value from a function, or use the sys.exit() method to exit the interpreter.

Here is an example of how the error occurs.

Copied! 
if len('hi') == 2: # ⛔️ SyntaxError: 'break' outside loop break 

The break statement can only be used inside of for or while loops.

Copied! 
# ✅ using break inside a for loop for i in range(5): if i == 3: break print(i) # 👉️ 0 1 2 print('exited for loop') 

The code sample above uses a break statement inside a for loop to exit the loop once the condition is met.

# Use a return statement to return a value from a function

If you meant to return a value from a function, use a return statement instead.

Copied! 
def example(): if len('hi') == 2: return 100 return 0 result = example() print(result) # 👉️ 100 

The return statement can be used to return a value and exit the function.

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Python Syntax Error, 'break' is outside the loop [closed]

Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.

Questions asking for code must demonstrate a minimal understanding of the problem being solved. Include attempted solutions, why they didn't work, and the expected results. See also: Stack Overflow question checklist

try: ip = float(input("Enter a number to find it's absolute value (press 'e' to exit):")) if ip == 'e': break 

Python is saying that break is outside of the loop. Does anyone have any ideas on how to fix this? Thanks in advance.

2 Answers 2

break cannot be used outside of loops.

If you are in a function, use return instead, or sys.exit() if not.

Actually, sys.exit() has similar semantics to break and return - it interrupts current flow, preventing further instructions to be parsed. pass wouldn't prevent that.

break can only be used to break out of a for-loop or a while-loop. If it is used anywhere else, an error will be thrown.

If you want to come out of a function, you need to use return . Or, if you want to exit the program, do this:

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SyntaxError: 'break' outside loop in python code

When running this code I keep getting the error SyntaxError: 'break' outside loop in python code after I enter any number (the first raw-input). I am trying to break the while-loop not the if-else loop which I think might be what's happening.

 import time import random players = raw_input("1 or 2 players? please enter ") if (players==1): name = raw_input("What is your name? ") print "Hello, " + name, "Time to play hangman!" print "\n" time.sleep(1) #wait for 1 second print "Start guessing. you only get 10 lives!" time.sleep(0.5) #here we set the secret word = 'ant car space stas satalite hubble amaing baboon badger bat bear beaver camel cat clam cobra cougar coyote crow deer dog donkey duck eagle ferret fox frog goat goose hawk lion lizard llama mole monkey moose mouse mule newt otter owl panda parrot pigeon python rabbit ram rat raven rhino salmon seal shark sheep skunk sloth snake spider stork swan tiger toad trout turkey turtle weasel whale wolf wombat zebra'.split() def getRandomWord(wordList): # This function returns a random string from the passed list of strings. wordIndex = random.randint(0, len(wordList) - 1) return wordList[wordIndex] guesses = '' #creates an variable with an empty value turns = 10 #determine the number of turns # Create a while loop while turns > 0: #check if the turns are more than zero failed = 0 # make a counter that starts with zero for char in word: # for every character in secret_word if char in guesses: # see if the character is in the players guess print char, # print then out the character else: print "_", # if not found, print a dash failed += 1 # and increase the failed counter with one if failed == 0: # if failed is equal to zero print "\nYou won" break # exit the script print guess = raw_input("guess a character:") # ask the user go guess a character guesses += guess # set the players guess to guesses if guess not in word: # if the guess is not found in the secret word turns -= 1 # turns counter decreases with 1 (now 9) print "Wrong\n" print "You have", + turns, 'more guesses' # how many turns are left if turns == 0: # if the turns are equal to zero print "You Loose\n" # print "You Loose" else: player1= raw_input("whats the secret word?") #welcoming the user name2= raw_input("What is the name of the guesser?") print "Hello, " + name2, "Time to play hangman!" print "\n" time.sleep(1) #wait for 1 second print "Start guessing. you only get 10 lives!" time.sleep(0.5) word2 = player1 guesses = '' #creates an variable with an empty value turns = 10 #determine the number of turns # Create a while loop while turns > 0: #check if the turns are more than zero failed = 0 # make a counter that starts with zero for char in word: # for every character in secret_word if char in guesses: # see if the character is in the players guess print char, # print then out the character else: print "_", # if not found, print a dash failed += 1 # and increase the failed counter with one if failed == 0: # if failed is equal to zero print "\nYou won" break # exit the script print guess = raw_input("guess a character:") # ask the user go guess a character guesses += guess # set the players guess to guesses if guess not in word: # if the guess is not found in the secret word turns -= 1 # turns counter decreases with 1 (now 9) print "Wrong\n" print "You have", + turns, 'more guesses' # how many turns are left if turns == 0: # if the turns are equal to zero print "You Loose\n" # print "You Loose" 

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Break Outside Loop Error in Python: Cause and Resolution

Hello coders!! In this article, we will be learning about the “break outside loop” loop error in Python. We will see its cause with some examples and will ultimately learn how to resolve this error. Let us now understand it in detail.

What does ‘break’ mean in Python?

The ‘break’ statement is used to instruct Python to exit from a loop. It is commonly used to exit a loop abruptly when some external condition is triggered. The break statement can be used in any type of loop – while loop and for loop.

n = 10 while n > 0: print ('Value :', n) n = n -1 if n == 5: break print ('Exiting the loop')

output:

As we can see, when the value of the variable becomes 5, the condition for the break statement triggers and Python exits the loop abruptly.

SyntaxError: break outside loop in Python:

The purpose of a break statement is to terminate a loop abruptly by triggering a condition. So, the break statement can only be used inside a loop. It can also be used inside an if statement, but only if it is inside a loop. If one uses a break statement outside of a loop, then they will get the “SyntaxError: ‘break’ outside loop” error in their code.

output:

We can see that the error SyntaxError: break outside loop occurs. This is because we have used the break statement without any parent loop.

Resolution for SyntaxError: break outside loop in Python:

The cause of the above error is that the break statement can’t be used anywhere in a program. It is used only to stop a loop from executing further.

We need to remove the break statements in order to solve the error. An exception can replace it. We use exceptions to stop a program and provide an error message.

Output:

The code now returns an exception based on the given condition. When we use an exception, it stops the program from further execution( if triggered) and displays the error message.

If we want the program to continue further execution, we cam simply use a print statement.

Output:

Here, due to the use of print statement, the program does not stop from execution.

Difference between break, exit and return:

BREAK	EXIT	RETURN
Keyword	System Call	Instruction
exit from a loop	exit from a program and return the control back to OS	return a value from a function

Conclusion: Break Outside Loop Python

In this article, we discussed in detail the Python “break out of loop error.” We learned about using the break statement and saw the scene in which the said error can occur. So, to avoid it, we must remember to use the break statement within the loop only.

However, if you have any doubts or questions, do let me know in the comment section below. I will try to help you as soon as possible.

Happy Pythoning!

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