Php принять post запрос json

Receiving JSON POST data via PHP.

In a previous tutorial, I showed how to send JSON data via POST in PHP. This led to somebody asking me how to receive JSON POST data with PHP.

To receive RAW post data in PHP, you can use the php://input stream like so:

//Receive the RAW post data via the php://input IO stream. $content = file_get_contents("php://input");

Now, let’s take a look at an example where we attempt to receive and validate JSON POST data:

 //Make sure that the content type of the POST request has been set to application/json $contentType = isset($_SERVER["CONTENT_TYPE"]) ? trim($_SERVER["CONTENT_TYPE"]) : ''; if(strcasecmp($contentType, 'application/json') != 0) < throw new Exception('Content type must be: application/json'); >//Receive the RAW post data. $content = trim(file_get_contents("php://input")); //Attempt to decode the incoming RAW post data from JSON. $decoded = json_decode($content, true); //If json_decode failed, the JSON is invalid. if(!is_array($decoded)) < throw new Exception('Received content contained invalid JSON!'); >//Process the JSON.

A drill-down of the code sample above:

1. We validate the request type by checking to see if it is POST. This will prevent the script from trying to process other request types such as GET.
2. We validate the content type. In this case, we want it to be application/json.
3. We retrieve the raw POST data from the php://input stream.
4. We attempt to decode the contents of the POST data from JSON into a PHP associative array.
5. We check to see if the result is an array. If it is not an array, then something has gone wrong. To debug the issue even further, be sure to check out this article on JSON error handling in PHP.
6. After that, we can process the associative array.

Hopefully, you found this tutorial to be helpful!

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How to extract and access JSON data in PHP

JavaScript Object Notation(JSON) is a lightweight human-readable text format for storing and transporting data consisting of name-value pairs and arrays.

It is easy to generate and parse in many programming languages. It is the most popular and lightweight data-interchange format for web applications and the de-facto format for the data exchange in RESTful web services requests and responses.

In this post, we will cover how to decode a JSON object and access its data in PHP.

Below is an example of a simple JSON object:

How to receive JSON data in PHP

1. From a POST or GET request

To receive JSON data as a POST request, we use the “php://input” along with the function file_get_contents() as below:

For instance, the JSON data is sent below as a POST request:

'; $curl = curl_init(); curl_setopt($curl, CURLOPT_URL, $url); curl_setopt($curl, CURLOPT_HTTPHEADER, array('Content-Type:application/json')); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_POST, true); curl_setopt($curl, CURLOPT_POSTFIELDS, $payload); curl_exec($curl); curl_close($curl); 

To receive the above request data in the register.php file, just add file_get_contents(«php://input») and assign it to a variable for processing eg:

2. Reading a JSON file

A JSON file contains a JSON object and has a file extension of .json. You can as well open the file in PHP and access its data.

Similar to POST or GET request, we use file_get_contents() but instead of having “php://input”, we use the file path.

For example, if we have a JSON file with path «https://www.example.com/mydata.json«, we can access its data as below:

If the json file and the PHP file accessing it are in the same website, we can use relative path instead of the full file URL.

Extracting/Decoding JSON data in PHP

We use the built-in function json_decode() to convert the JSON string to the appropriate data type such as an object or an array.

1. Accessing JSON data as a PHP object

By default the json_decode() function returns an object.

Example
The example below decodes a JSON object into a PHP object:

'; $data = json_decode($json); var_dump($data); 

The above example outputs below:

object(stdClass)#1 (4) < ["firstName"]=>string(4) «John» [«lastName»]=> string(3) «Doe» [«email»]=> string(17) «johndoe@gmail.com» [«phone»]=> string(12) «111-111-1111» >

To access the PHP object data, you use the object operator (->) after the object name, followed by the key of the key-value pair. This is the same as the name in the name-value pair in JSON object eg $data->firstName .

'; $data = json_decode($json); echo "My name is".$data->firstName." ".$data->lastName; //Output: My name is John Doe 

2. Accessing JSON data as an array

You can as well convert the JSON object to a PHP associative array by passing a second(optional) parameter in the json_decode() function with the boolean value «true» as below. The value is set to false by default if you don’t pass it.

The example below decodes JSON object into a PHP associative array:

'; $data = json_decode($json, true); var_dump($data); 

The above example outputs below:

array(4) < ["firstName"]=>string(4) «John» [«lastName»]=> string(3) «Doe» [«email»]=> string(17) «johndoe@gmail.com» [«phone»]=> string(12) «111-111-1111» >

You access the data as in any other PHP associative array as in the example below:

'; $data = json_decode($json, true); echo "My name is ".$data["firstName"]." ".$data["lastName"]; //Output: My name is John Doe 

3. Accessing data in a nested JSON object

A JSON object may comprise of json objects and arrays as the values in its name-value pairs such as in the example below:

In the above example, the «address» has an object as its value while «siblings» has an array value comprising of objects.

The easiest way of accessing all the data is decoding the object as an associative array.

, "siblings": [ < "name": "Joseph Doe" >, < "name": "Mary Doe" >] >'; $data = json_decode($json, true); //Displaying all the data echo "First Name: ".$data["firstName"]."
"; //Output -> First Name: John echo "First Name: ".$data["lastName"]."
"; //Output -> Last Name: Doe echo "Email Address: ".$data["email"]."
"; //Output -> Email Address: johndoe@gmail.com echo "Postal Address: ".$data["address"]["postalAddress"]."
"; //Output -> Postal Address: 12345 echo "Postal Code: ".$data["address"]["postalCode"]."
"; //Output -> Postal Code: 5432 echo "City: ".$data["address"]["city"]."
"; //Output -> City: Nairobi echo "Sibling 1: ".$data["siblings"][0]["name"]."
"; //Output -> Sibling 1: Joseph Doe echo "Sibling 2: ".$data["siblings"][1]["name"]."
"; //Output -> Sibling 2: Mary Doe 

Looping through an object of objects with foreach()

You may have a large JSON object made of an array of objects, like in the example below:

To access the values of a country in the example above, you just have to know its object position in the array. For example, china is in the third position. But when accessing the array items, we start counting from 0, hence the index of China in the array is 2.

We access the China array object as below:

"; //Output -> Country: China echo "Code: ".$data["countries"][2]["code"]."
"; //Output -> Code: CN echo "City: ".$data["countries"][2]["city"]."
"; //Output -> City: Beijing 

If you want to access all the array data then it can be tiresome and time-consuming to write the code for accessing each at a time especially when the object is large. For such an instance, you can use the foreach() function to loop through all the objects as below:

, < "name": "India", "code": "IN", "city": "New Delhi" >, < "name": "China", "code": "CN", "city": "Beijing" >, < "name": "Germany", "code": "DE", "city": "Berlin" >, < "name": "Kenya", "code": "KE", "city": "Nairobi" >] >'; $countries = json_decode($json)->countries; foreach($countries as $country)< echo "Country: ".$country->name."
"; echo "Code: ".$country->code."
"; echo "City: ".$country->city."
"; > 

Conclusion

In this post, we have covered everything you need to know in extracting and accessing a JSON object data using PHP.

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Reading JSON POST using PHP

I looked around a lot before posting this question so my apologies if it is on another post and this is only my second quesiton on here so apologies if I don’t format this question correctly. I have a really simple web service that I have created that needs to take post values and return a JSON encoded array. That all worked fine until I was told I would need to post the form data with a content-type of application/json. Since then I cannot return any values from the web service and it is definitely something to do with how I am filtering their post values. Basically in my local setup I have created a test page that does the following —

$curl = curl_init(); curl_setopt($curl, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($curl, CURLOPT_POSTFIELDS, $data); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_HTTPHEADER, array( 'Content-Type: application/json', 'Content-Length: ' . strlen($data)) ); curl_setopt($curl, CURLOPT_URL, 'http://webservice.local/'); // Set the url path we want to call $result = curl_exec($curl); //see the results $json=json_decode($result,true); curl_close($curl); print_r($json); 

1, 'statusDescription'=>'Login Process - Fail'); $posts[] = array('status'=>$statusCode); header('Content-type: application/json'); echo json_encode($posts); /* disconnect from the db */ > @mysql_close($link); ?> 

Basically I know that it is due to the $_POST values not being set but I can’t find what I need to put instead of the $_POST. I tried json_decode($_POST), file_get_contents(«php://input») and a number of other ways but I was shooting in the dark a bit. Any help would be greatly appreciated. Thanks, Steve Thanks Michael for the help, that was a definite step forward I now have at least got a repsonse when I echo the post. even if it is null updated CURL —

 $curl = curl_init(); curl_setopt($curl, CURLOPT_HTTPHEADER, array('Content-Type: application/json')); curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($curl, CURLOPT_URL, 'http://webservice.local/'); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_POSTFIELDS, json_encode($data)); 

$inputJSON = file_get_contents('php://input'); $input= json_decode( $inputJSON, TRUE ); //convert JSON into array print_r(json_encode($input)); 

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Read JSON request data with PHP

While working on an API project, I realised that I actually didn’t know how to receive JSON data in the request body with PHP. Turns out it’s really simple with the php://input stream.

Most projects we work on with PHP rely on forms to receive data. That’s what the $_POST superglobal is for: it contains all information passed via HTTP POST when sending data with content type application/x-www-form-urlencoded or multipart/form-data .

But what if you use the application/json content type? Up until PHP 5.6 we could use the $HTTP_RAW_POST_DATA superglobal, but this has been deprecated. Instead we should use the php://input stream to read raw data from the request body.

Below is an example script. The comments explain what’s happening:

 // Only allow POST requests if (strtoupper($_SERVER['REQUEST_METHOD']) != 'POST') < throw new Exception('Only POST requests are allowed'); > // Make sure Content-Type is application/json $content_type = isset($_SERVER['CONTENT_TYPE']) ? $_SERVER['CONTENT_TYPE'] : ''; if (stripos($content_type, 'application/json') === false) < throw new Exception('Content-Type must be application/json'); > // Read the input stream $body = file_get_contents("php://input"); // Decode the JSON object $object = json_decode($body, true); // Throw an exception if decoding failed if (!is_array($object)) < throw new Exception('Failed to decode JSON object'); > // Display the object print_r($object); 

Let’s give this a quick whirl. Save the example as script.php and start the standalone PHP server with php -S localhost:8080 script.php .

Now let’s send it a POST request containing JSON data using cURL:

curl -X POST \ -d '' \ -H "Content-Type: application/json" \ http://localhost:8080

Your JSON object should be printed out:

Array ( [foo] => Array ( [0] => bar [1] => baz ) )

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