preg match со страницы с расширением json
У меня есть одна страница в формате JSON, и я хочу удалить некоторые данные с этой страницы.
Мне нужно отменить это «значение»: «6fc975cd-bbd4-2daa-fc6b-1e8623f80caf | Антенны & Фильтр товаров | Фильтр товаров »
это моя страница JSON
Это моя функция для preg матча
public function getcategories( $page = '' ) < $results = array(); preg_match_all( '~/\[value\]\s=>\s(.*?)\s*\[~', $page, $matchall ); debug($matchall);die; if ( !empty( $matchall[1] ) ) < foreach ( $matchall[1] as $single ) < if ( strlen( $single ) >1 ) < $results[] = $single; >> > return $results; > И я называю эту функцию здесь
function checkpage( $page = '' ) < $vars_all_array = $this->getvarsallfrompage( $page ); $get_api_url = $this->catspostreq($page); $post_data = $this->makePostData( $vars_all_array, 0, 25 ); $jsonpage = $this->get_page( $get_api_url, array ('data' => $post_data, 'content-type'=> 'application/x-www-form-urlencoded; charset="UTF-8"; application/json' ) ); $json_decoded = json_decode($jsonpage); $categories = $this->getcategories( $json_decoded ); debug($categories);die; > Но что-то не работает хорошо, у меня есть эта ошибка:
preg_match_all () ожидает, что параметр 2 будет строкой, задан массив
Кто-нибудь может мне помочь?
Решение
Вам не нужно делать preg_match_all, чтобы получить значение из $json_decoded , как json_decode() вернет (в случае успеха) отлично читаемый массив или объект.
Таким образом, чтобы получить одно конкретное значение, вы можете получить к нему доступ следующим образом:
$value = $json_decoded['groupByResults'][0]->values[0]->value; Так как вы хотите иметь все значения в новом массиве, вы можете просто перебрать значения и передать их в новый массив:
$categories = []; foreach($json_decoded['groupByResults'][0]->values as $item)
Есть встроенные функции массива, которые делают это в одну строку и, возможно, быстрее. Это для иллюстрации того, что вы делаете с данными.
Используя такую функцию array_column () приведет к этой однострочник:
$categories = array_column($json_decoded['groupByResults'][0]->values, "value"); Другие решения
В вашем checkpage Функция, которую вы передаете значение json_decode к getcategories функция как параметр, который в большинстве случаев возвращает массив. и ваш getcategories Вы передаете $page параметр в качестве второго параметра preg_match_all
$json_decoded = json_decode($jsonpage); $categories = $this->getcategories( $json_decoded ); preg_match_all('~/\[value\]\s=>\s(.*?)\s*\[~', $page, $matchall); здесь $ page является результатом json_decode который является массивом. вот почему вы получаете эту ошибку
php preg_match find difficult JSON from string
Here is a simple way to get your content without needing to use lookarounds:
preg_match('~var vars = (\<.*?\>;)~m', $get, $json_matches); $json_match = $json_matches[1]; print $json_match; I am pretty much just matching all of the data between the curly braces from one to the other.
Quixrick 3160
Read More
Just use lookbehind and lookahead:
n-dru 9202
With a positive lookahead and a lazy quantifier (modified according to your comments):
;)>;)~'; preg_match_all($regex, $file, $matches); $code = $matches[1][0]; echo $code; ?> See a demo on regex101.com. This works, however it is very slow and error-prone. Is there some other way to get the code in question?
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