Launch exe file java

Create Windows Executable (.exe) for Java Application

Launch4j is a cross-platform tool for wrapping Java applications distributed as jars in lightweight Windows native executable files. In this post, we will learn making such an executable file for a demo java application.

Step1 ) Create a java application

I am creating a very basic java class which simply displays a frame and some text on it. It also has the main() method which will start the application.

package com.howtodoinjava; import java.awt.Color; import java.awt.Font; import java.awt.Frame; import java.awt.Label; import java.awt.event.WindowAdapter; import java.awt.event.WindowEvent; import javax.swing.JDialog; public class ApplicationMain extends JDialog < private static final long serialVersionUID = 1L; public ApplicationMain() < //Create a frame Frame f = new Frame(); f.setSize(500, 300); //Prepare font Font font = new Font( "SansSerif", Font.PLAIN, 22 ); //Write something Label label = new Label("Launch4j Maven Demo with HowToDoInJava.com"); label.setForeground(Color.RED); label.setFont(font); f.add(label); //Make visible f.setVisible(true); f.addWindowListener(new WindowAdapter() < public void windowClosing(WindowEvent e) < System.exit(0); >>); > public static void main(final String[] args) < new ApplicationMain(); >>

Step 2) Create maven file with launch4j configured in it

I have created a pom file for packaging the application as .exe file. If you feel something unclear, drop a comment.

 4.0.0 com.howtodoinjava JavaExeDemo jar 1.0-SNAPSHOT JavaExeDemo http://maven.apache.org UTF-8    org.apache.maven.plugins maven-compiler-plugin 2.5.1 1.6 1.6   org.apache.maven.plugins maven-shade-plugin 1.7.1  package shade    true shaded  com.howtodoinjava.Main     com.akathist.maven.plugins.launch4j launch4j-maven-plugin 1.5.1  l4j-clui package launch4j  gui $/$-$-shaded.jar $/howtodoinjava.exe http://java.com/download com.howtodoinjava.ApplicationMain anything  application.ico 1.6.0 preferJre  1.0.0.0 $ $ 2012 howtodoinjava.com 1.0.0.0 1.0.0.0 $ howtodoinjava.com howtodoinjava howtodoinjava.exe         

Step 3) Create .exe file

To make the exe file for above java program, run maven command:

Above command will create the “howtodoinjava.exe ” file in your project’s target folder. Double click on .exe file will open the window like this.

Launch4j maven demo to create java executable

If you want to download source code of above application, click on below given download link.

Happy Learning !!

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How to run a *.exe file in Java

Greetings, I was wondering if someone could teach me how to run an executable in java. I have written a Java program that fills out some information, but I need to run a file that is normally run from a command prompt that is an executable. If someone could tell me how to do this, I would appreciate it. Thanks.
Sciocosmist

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  • Latest Post 13 Years Ago Latest Post by peter_budo

>has a problem with the output file name becase it is technically not created yet. Would any one have a solution for how I would be able to have the output file included?

I would guess that the file has to be opened, written then closed before you can …

anybody,
can u help me in this
how to run an exe file which is generated through c program in java

its urgent
plz

Read all previous replies. Your urgency unfortunately doesn’t mean anything to us.
Closing thread as there is no need for more bumps to reopen thread and …

All 13 Replies

Thank you for your help! This is close to what I needed. On the *.exe file it has a command line sequence of: command=(path of program)/name of program.exe (upload file #1)=(path file#1) (upload file #2)=(path file#2) (output file name)=(name for output) /exit That is to say that the variable command=the path of the *.exe program, space, first needed file, space, second file needed, space, output name, space, /exit. The java command: Runtime.getRuntime().exec(command); //command is a variable has a problem with the output file name becase it is technically not created yet. Would any one have a solution for how I would be able to have the output file included?

>has a problem with the output file name becase it is technically not created yet. Would any one have a solution for how I would be able to have the output file included? I would guess that the file has to be opened, written then closed before you can launch it as an executable. Is that what you mean?

A command prompt would come up and say ‘Windows does not recognize (new file name)’
After a bit of investigation, I have found that the command for the runtime process needs to have a destination/working directory where the program is stored. Here is what I am attempting to do: String command=»(path of program)/name of program.exe /(upload file #1)=(path file#1) /(upload file #2)=(path file#2) /(output file name)=(name for output) /exit» That is to say that the variable command=the path of the *.exe program, space, forward slash, program recognition code, equals sign, first needed file, space, forward slash, program recognition code, equals sign, second file needed, space, forward slash, program recognition code, equals sign, output name, space, /exit. The java command: Process p=Runtime.getRuntime().exec(«rundll32 SHELL32.DLL,ShellExec_RunDLL «+ command); //command is a variable p.waitFor();//to allow the program to terminate before proceeding.
Since this is an *.exe it needs to have certain addional files not listed in the original command line prompt from the Java code, in order to execute. Could you also tell me how to set the correct directory so that the command line would know where to find the necessary files to execute the *.exe? I have tried to use the System.getenv(. ) method, but that didn’t work. Again thank you, and anyone else willing to help! —Sciocosmist

I am trying to run the program from a method as oppossed to using the main method. Could any one give me some advice on how to run the Runtime.getRunTime.exec(. ) method for a *.exe file with three needed arguments without using the «public static void main (String[] args) method? I cannot use a main method to pass parameters in with the program that I am coding. The first argument is a file that I have created with my Java program. The second argument is a file that I also have created with my Java program. The third argument is the output name of the *.exe file (the *.exe file writes a file based on the information from the other two files).

I’m not sure I’m following the details of the problems you are having, but more generally, have a look at the [new] «ProcessBuilder» class in the standard java API docs. It gives you better control over the command line arguments and also the working directory that the process appears to run in. In other words, it is better than Runtime’s exec.

The executable that I am trying to run is a MSDOS based program. I need to pass in parameters to the command line. I have been able to get windows based *.exe files to run, but not an MSDOS application to run from the Java Code. Here is the command that I need to run from a command prompt (and in the java program I am writing):

C:\My Directory\My_exe.exe /cfg=my_cfg.cfg /err=my_xmd.xmd /xml=My_xml.xml /exit

Where both the *.cfg and the *.xmd are files that are read by the *.exe program. The *.xml is the name for the output file that the *.exe program produces. This does work in a command prompt or command line, but it does not work in Java code (so far as I have tried). Here is some of what I have tried:
Example 1:

Process p=Runtime.getRuntime().exec("rundll32 SHELL32.DLL,ShellExec_RunDLL " +"C:\\My Directory\\My_exe.exe /cfg=my_cfg.cfg /err=my_xmd.xmd /xml=My_xml.xml /exit"); Thread needle =new Thread(); needle.sleep(((y/120)*1500+15000));//y is an int that is obtained from different sources throughout the program; I have checked it and it is fine. p.destroy();//By this time the process has closed and I can close the window. The waitFor() command does not work for my purposes.
ProcessBuilder pb=new ProcessBuilder("cmd.exe /c start C:\\My Directory\\My_exe.exe /cfg=my_cfg.cfg /err=my_xmd.xmd /xml=My_xml.xml /exit"); pb.directory(new File("C:\\My Directory\\My_exe.exe")); Process p=pb.start(); Thread needle =new Thread(); needle.sleep(((y/120)*1500+15000));//y is an int that is obtained from different sources throughout the program; I have checked it and it is fine. p.destroy();//By this time the process has closed and I can close the window. The waitFor() command does not work for my purposes.
Process p=Runtime.getRuntime().exec("C:\\My Directory\\My_exe.exe /cfg=my_cfg.cfg /err=my_xmd.xmd /xml=My_xml.xml /exit"); Thread needle =new Thread(); needle.sleep(((y/120)*1500+15000));//y is an int that is obtained from different sources throughout the program; I have checked it and it is fine. p.destroy();//By this time the process has closed and I can close the window. The waitFor() command does not work for my purposes.
Process p=Runtime.getRuntime().exec("rundll32 SHELL32.DLL,ShellExec_RunDLL " +"C:\\My Directory\\My_pif.pif");//The pif file contains the string as listed above Thread needle =new Thread(); needle.sleep(((y/120)*1500+15000));//y is an int that is obtained from different sources throughout the program; I have checked it and it is fine. p.destroy();//By this time the process has closed and I can close the window. The waitFor() command does not work for my purposes.
Process p=Runtime.getRuntime().exec("C:\\My Directory\\My_bat.bat");//the *.bat contains the string listed above. Thread needle =new Thread(); needle.sleep(((y/120)*1500+15000));//y is an int that is obtained from different sources throughout the program; I have checked it and it is fine. p.destroy();//By this time the process has closed and I can close the window. The waitFor() command does not work for my purposes.

I have tried variations of each of these, but it has not yet been able to run. If someone could help me out, I would appreciate it. Thank you for your help!

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