Java urldecoder illegal hex characters in escape

Escape pattern containing illegal hex characters in URL decoder

Using only URL encoding with the % character and two hexadecimal digits can encode characters that may cause problems. For instance, if a character has an ASCII code of 47 (decimal) or 2F (hex), it would be encoded as %. Additionally, characters that have % and + signs in them are also encoded. Despite being helpful with % and + characters in a string, it doesn’t decode things like %20 (space) since the percent is removed before decoding.

URLDecoder: Illegal hex characters in escape (%) pattern

The accepted answer has a significant problem. Encoded characters contain % and + signs, which means that while this approach is useful for handling % and + characters in a string, it fails to decode characters like %20 (representing a space) because the percent is removed prior to decoding.

An alternative to consider is substituting the symbols %2B (+) and %25 (%) with something else. For example:

 public static String replacer(StringBuffer outBuffer) < String data = outBuffer.toString(); try < data = data.replaceAll("%(?![0-9a-fA-F])", "%25"); data = data.replaceAll("\\+", "%2B"); data = URLDecoder.decode(data, "utf-8"); > catch (Exception e) < e.printStackTrace(); >return data; > 

The symbol «+» holds a unique meaning as it represents a quantifier indicating one or more occurrences. Hence, it’s advisable to utilize the escape character «\+» instead of «+».

The link for URLDecoder can help you understand the cause of this exception that I have discovered.

Prior to invoking URLDecoder.decode() , I performed the following actions.

public static String replacer(StringBuffer outBuffer) < String data = outBuffer.toString(); try < StringBuffer tempBuffer = new StringBuffer(); int incrementor = 0; int dataLength = data.length(); while (incrementor < dataLength) < char charecterAt = data.charAt(incrementor); if (charecterAt == '%') < tempBuffer.append(""); > else if (charecterAt == '+') < tempBuffer.append(""); > else < tempBuffer.append(charecterAt); >incrementor++; > data = tempBuffer.toString(); data = URLDecoder.decode(data, "utf-8"); data = data.replaceAll("", "%"); data = data.replaceAll("", "+"); > catch(Exception e) < e.printStackTrace(); >return data; > 

String stringEncoded = URLEncoder.encode(**YOUR_TEXT**, "UTF-8"); 

The issue of «darkness» arose during my usage of servlets.

Java — URLDecoder: Illegal hex characters in escape (%), How do I properly decode the string which contains % in Java When I use URLDecoder.decode() i am getting the following error: IllegalArgumentException: java.lang.IllegalArgumentException: URLDecoder: Illegal hex characters in escape (%) pattern — For input string: «.P» at …

URLDecoder: Illegal hex characters in escape (%) pattern

Attempting to URL decode content that was not originally URL encoded appears to be the issue. Is there a problem with leaving the content as is? In essence, what would occur if you simply utilized:

To encode problematic characters in URL encoding, the % symbol is used along with two hexadecimal digits. For instance, if the ASCII code of a character is 47 (decimal) or 2F (hex), like / , it would be encoded as %2F . The decoder is erroring because % in your body is not URL encoded since it is followed by non-hexadecimal characters.

Cease invoking URLDecoder.decode() to evade the error. It occurs because the value of the string you pass is not encoded in URL format.

If you need to send an email containing content that would otherwise be prohibited, you may want to explore the different MIME encoding options available. The following references could prove useful.

1. The items permitted in SMTP can be found at http://www.apps.ietf.org/rfc/rfc788.html.
2. The fundamentals of MIME encoding can be found at http://www.apps.ietf.org/rfc/rfc1341.html.
3. Access documentation for Java’s MIME support through the following link: http://docs.oracle.com/javaee/1.4/api/javax/mail/internet/MimeUtility.html.

For example, you might try:

String sendable = MimeUtility.encodeText(body,"UTF-8","BASE64") 

Apache CXF REST multipart upload, encoding exception, 1 Answer. The issue got solved on the Apache CXF mailing list by Sergey Beryozkin. What happens with this declaration is that the form payload processor assumes the last parameter being just one more plain multipart/form-data parameter. When you have a ‘mixed’ multipart/form-data payload, …

Hadoop Pig: URLDecoder: Illegal hex characters in escape (%) pattern

To resolve this issue, I applied the given pig code prior to executing the UrlDecode function.

REPLACE(facets, 'u2', '') as facets 

Urlencode — Trying to decode % character in a parameter, Uncaught Exception java.lang.IllegalArgumentException: URLDecoder: Illegal hex characters in escape(%) pattern — For input string: «xy». See log file for details. I cannot escape the character using backslash asdf\%xy3dsfsfsf since it would get to the webservice as the incorrect password. Please advice on …

501 Method not implemented — URLDecoder: Illegal hex characters in escape (%) pattern

The Unicode representation of the en dash is denoted by the %u2013 symbol.

JMeter: java.lang.IllegalArgumentException, Looks like your are trying to decode an improperly encoded (or not at all encoded) value. See Trying to decode % character in a parameter value JMeter fails with IllegalArgumentException: URLDecoder: Illegal hex characters in escape(%) pattern for more details. If your are unfamiliar with encoding of query …

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URLDecoder: Illegal hex characters in escape (%) pattern — For input string: » S» #747

URLDecoder: Illegal hex characters in escape (%) pattern — For input string: » S» #747

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«org.elasticsearch» % «elasticsearch-spark_2.11» % «2.3.0»

[error] (run-main-0) java.lang.IllegalArgumentException: URLDecoder: Illegal hex characters in escape (%) pattern - For input string: " S" java.lang.IllegalArgumentException: URLDecoder: Illegal hex characters in escape (%) pattern - For input string: " S" at java.net.URLDecoder.decode(URLDecoder.java:194) at org.elasticsearch.hadoop.util.StringUtils.decodeQuery(StringUtils.java:404) at org.elasticsearch.hadoop.util.StringUtils.tokenizeAndUriDecode(StringUtils.java:135) at org.elasticsearch.hadoop.serialization.dto.mapping.MappingUtils.validateMapping(MappingUtils.java:45) at org.elasticsearch.hadoop.rest.RestService.findPartitions(RestService.java:271) at org.elasticsearch.spark.rdd.AbstractEsRDD.esPartitions$lzycompute(AbstractEsRDD.scala:61) at org.elasticsearch.spark.rdd.AbstractEsRDD.esPartitions(AbstractEsRDD.scala:60) at org.elasticsearch.spark.rdd.AbstractEsRDD.getPartitions(AbstractEsRDD.scala:27) at org.apache.spark.rdd.RDD$$anonfun$partitions$2.apply(RDD.scala:239) at org.apache.spark.rdd.RDD$$anonfun$partitions$2.apply(RDD.scala:237) at scala.Option.getOrElse(Option.scala:121) at org.apache.spark.rdd.RDD.partitions(RDD.scala:237) at org.apache.spark.rdd.MapPartitionsRDD.getPartitions(MapPartitionsRDD.scala:35) at org.apache.spark.rdd.RDD$$anonfun$partitions$2.apply(RDD.scala:239) at org.apache.spark.rdd.RDD$$anonfun$partitions$2.apply(RDD.scala:237) at scala.Option.getOrElse(Option.scala:121) at org.apache.spark.rdd.RDD.partitions(RDD.scala:237) at org.apache.spark.rdd.MapPartitionsRDD.getPartitions(MapPartitionsRDD.scala:35) at org.apache.spark.rdd.RDD$$anonfun$partitions$2.apply(RDD.scala:239) at org.apache.spark.rdd.RDD$$anonfun$partitions$2.apply(RDD.scala:237) at scala.Option.getOrElse(Option.scala:121) at org.apache.spark.rdd.RDD.partitions(RDD.scala:237) at org.apache.spark.sql.execution.SparkPlan.executeTake(SparkPlan.scala:190) at org.apache.spark.sql.execution.Limit.executeCollect(basicOperators.scala:165) at org.apache.spark.sql.execution.SparkPlan.executeCollectPublic(SparkPlan.scala:174) at org.apache.spark.sql.DataFrame$$anonfun$org$apache$spark$sql$DataFrame$$execute$1$1.apply(DataFrame.scala:1499) at org.apache.spark.sql.DataFrame$$anonfun$org$apache$spark$sql$DataFrame$$execute$1$1.apply(DataFrame.scala:1499) at org.apache.spark.sql.execution.SQLExecution$.withNewExecutionId(SQLExecution.scala:56) at org.apache.spark.sql.DataFrame.withNewExecutionId(DataFrame.scala:2086) at org.apache.spark.sql.DataFrame.org$apache$spark$sql$DataFrame$$execute$1(DataFrame.scala:1498) at org.apache.spark.sql.DataFrame.org$apache$spark$sql$DataFrame$$collect(DataFrame.scala:1505) at org.apache.spark.sql.DataFrame$$anonfun$head$1.apply(DataFrame.scala:1375) at org.apache.spark.sql.DataFrame$$anonfun$head$1.apply(DataFrame.scala:1374) at org.apache.spark.sql.DataFrame.withCallback(DataFrame.scala:2099) at org.apache.spark.sql.DataFrame.head(DataFrame.scala:1374) at org.apache.spark.sql.DataFrame.take(DataFrame.scala:1456) at org.apache.spark.sql.DataFrame.showString(DataFrame.scala:170) at org.apache.spark.sql.DataFrame.show(DataFrame.scala:350) at org.apache.spark.sql.DataFrame.show(DataFrame.scala:311) at org.apache.spark.sql.DataFrame.show(DataFrame.scala:319) at com.rklick.engine.example.ESDataTest$.main(ESDataTest.scala:44) at com.rklick.engine.example.ESDataTest.main(ESDataTest.scala) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:498) 

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URLDecoder: Недопустимые шестнадцатеричные символы в шаблоне escape (%) – для строки ввода: «

Я получаю это исключение, пытаясь сгенерировать файл .PDF из моего приложения.

URLDecoder: Illegal hex characters in escape (%) pattern - For input string. 

java.lang.IllegalArgumentException: URLDecoder: Illegal hex characters in escape (%) pattern - For input string: " 

StringBuffer outBuffer = new StringBuffer(); //some values are added to outBuffer . String pdfXmlView = URLDecoder.decode(outBuffer.toString(), "utf-8"); 

При попытке декодирования с помощью URLDecoder.decode() он выдает это исключение. Я получил причину исключения, он приходит из-за% -ного характера в outBuffer.

Если кто-нибудь знает, как решить эту проблему, пожалуйста, помогите мне.

Поэтому перед вызовом URLDecoder.decode() я сделал это…

public static String replacer(StringBuffer outBuffer) < String data = outBuffer.toString(); try < StringBuffer tempBuffer = new StringBuffer(); int incrementor = 0; int dataLength = data.length(); while (incrementor < dataLength) < char charecterAt = data.charAt(incrementor); if (charecterAt == '%') < tempBuffer.append(""); > else if (charecterAt == '+') < tempBuffer.append(""); > else < tempBuffer.append(charecterAt); >incrementor++; > data = tempBuffer.toString(); data = URLDecoder.decode(data, "utf-8"); data = data.replaceAll("", "%"); data = data.replaceAll("", "+"); > catch(Exception e) < e.printStackTrace(); >return data; > 

Существует серьезная проблема с принятым ответом. Символы, которые получают кодировку, имеют в них знаки% и +, поэтому, хотя это помогает с символами% и + в строке, он также не декодирует такие вещи, как %20 (пробел), потому что вы извлекаете процент перед декодированием.

Решение заключается в замене% 2B (+) и% 25 (%). Что-то вроде:

 public static String replacer(StringBuffer outBuffer) < String data = outBuffer.toString(); try < data = data.replaceAll("%(?![0-9a-fA-F])", "%25"); data = data.replaceAll("\\+", "%2B"); data = URLDecoder.decode(data, "utf-8"); > catch (Exception e) < e.printStackTrace(); >return data; > 

“+” – специальный символ, обозначающий квантификатор, означающий одно из других вхождений. Поэтому следует использовать “\ +”

Пожалуйста, проверьте свой ввод в декодере, внешний буфер, который был передан методу декодера, должен быть закодированным значением, тогда эта проблема не будет возникать.

If you are facing issue only with **%**. Then this would help: protected static String encoder(String localTopic1) < String localTopic =localTopic1; try < StringBuffer tempBuffer = new StringBuffer(); int incrementor = 0; int dataLength = localTopic.length(); while (incrementor < dataLength) < char characterAt = localTopic.charAt(incrementor); int next_char_index = incrementor+1; int third_index = next_char_index+1; Character charAt_nextIndex = ' '; char charAt_thirdIndex = ' '; String stringAt_nextIndex = ""; if(next_char_index < dataLength)< charAt_nextIndex = localTopic.charAt(next_char_index); stringAt_nextIndex = charAt_nextIndex.toString(); >if(third_index < dataLength) charAt_thirdIndex = localTopic.charAt(third_index); if (characterAt == '%') < if(stringAt_nextIndex.matches("[A-F2-9]"))< if(charAt_thirdIndex == ' ' || charAt_thirdIndex == '%')< tempBuffer.append(""); > else < tempBuffer.append(characterAt); >> else< tempBuffer.append(""); > >else < tempBuffer.append(characterAt); >incrementor++; > localTopic = tempBuffer.toString(); > catch (Exception e) < e.printStackTrace(); >return localTopic; > 

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