Java runtime cannot run program createprocess error 2

«Cannot run program» when using Runtime.exec with spaces in program filename

browser + filename would be C:/Program Files (x86)/Google/Chrome/Application/chrome.exeC:/sample.html , notice any additional problems with that?

Read (and implement) all the recommendations of When Runtime.exec() won’t. That might solve the problem. If not, it should provide more information as to the reason it failed. Then ignore that it refers to exec and build the Process using a ProcessBuilder . Also break a String arg into String[] args to account for arguments which themselves contain spaces.

4 Answers 4

Runtime.exec(String) automatically splits the string at spaces, assuming the first token is the command name and the rest are command line parameters. Also you do not have a space between browser and file , although that is not the root cause of the problem.

It thinks you want to run «C:/Program» with two command line arguments:

Use Runtime.exec(String[]) instead, that way you have full control over what is what:

 String[] command = new String[]; Runtime.exec(command); 

@Bohemian No, that’s not true. Runtime.exec(String,String[],File) (and therefore Runtime.exec(String) uses a StringTokenizer with default settings to split the command string into a command and parameters. Runtime.exec(«a b c») attempts to run «a» with two parameters, «b» and «c».

Stop using Runtime.exec(String) — the problem is in how it processes the single string input.

The error message indicates how/where it is failing: note that it stops after «C:/Program» (or, the first space). This indicates that exec parsed the string «incorrectly» and thus isn’t even looking for the correct executable.

Instead, consider the use of ProcessBuilder. While the usage is still system-dependent, ProcessBuilder allows separation of the executable file-name (and need to deal with it specially) and the arguments and does it’s darnedest to invoke the target correctly.

String filename = "C:\\sample.html"; String browser = "C:\\Program Files (x86)\\Google\\Chrome\\Application\\chrome.exe"; ProcessBuilder pb = new ProcessBuilder(browser, filename); // setup other options .. // .. and run Process p = pb.start(); p.waitFor(); 

From what I can tell, in Windows, ProcessBuilder will wraps the individual components in quotes; this can create a different problem when arguments contain quotes..

Источник

How to fix java.io.ioexception: cannot run program «dir»: createprocess error=2, das system?

The java.io.IOException: Cannot run program «dir»: CreateProcess error=2, The system cannot find the file specified error message is thrown when the Java code is trying to run a system command or program using the java.lang.ProcessBuilder class, and the specified program or command is not found in the PATH environment variable. In order to fix this issue, there are several methods that can be followed:

Method 1: Check if the program is installed

To fix the «java.io.IOException: Cannot run program «dir»: CreateProcess error=2, Das System?» error, you can check if the program is installed before executing it. Here’s an example code:

import java.io.IOException; public class ProgramChecker  public static void main(String[] args)  String program = "dir"; // replace with your program name try  Process process = new ProcessBuilder("where", program).start(); int exitCode = process.waitFor(); if (exitCode == 0)  System.out.println(program + " is installed."); // execute the program here > else  System.out.println(program + " is not installed."); // handle the error here > > catch (IOException | InterruptedException e)  e.printStackTrace(); > > >

This code uses the ProcessBuilder class to execute the where command, which searches for the program in the system’s path. If the program is found, the exitCode will be 0, indicating success. If the program is not found, the exitCode will be non-zero, indicating failure.

You can replace the program variable with the name of the program you want to check. If the program is installed, you can execute it by adding the code to the if block. If the program is not installed, you can handle the error by adding the code to the else block.

This code can be split into the following steps:

1. Import the java.io.IOException class.
2. Create a ProgramChecker class.
3. Define the main method.
4. Set the program variable to the name of the program you want to check.
5. Use the ProcessBuilder class to execute the where command with the program argument.
6. Get the exitCode of the process.
7. Check if the exitCode is 0 to see if the program is installed.
8. If the program is installed, execute it.
9. If the program is not installed, handle the error.

This approach can help you avoid the «java.io.IOException: Cannot run program» error by checking if the program is installed before executing it.

Method 2: Specify the full path of the program

To fix the «java.io.IOException: Cannot run program «dir»: CreateProcess error=2, Das System?» error in Java, you can specify the full path of the program you want to run. Here’s how:

1. First, get the full path of the program you want to run. For example, if you want to run the «dir» command on Windows, the full path is «C:\Windows\System32\cmd.exe».
2. In your Java code, use the ProcessBuilder class to create a new process and specify the full path of the program as the command. Here’s an example:

String command = "C:\\Windows\\System32\\cmd.exe /c dir"; ProcessBuilder pb = new ProcessBuilder(command); Process process = pb.start();

In this example, the «/c» option is used to run the «dir» command and then exit the command prompt.

1. You can also set the working directory for the process using the ProcessBuilder’s directory() method. For example:

String command = "C:\\Windows\\System32\\cmd.exe /c dir"; ProcessBuilder pb = new ProcessBuilder(command); pb.directory(new File("C:\\Users\\JohnDoe\\Documents")); Process process = pb.start();

In this example, the working directory for the process is set to «C:\Users\JohnDoe\Documents».

1. Finally, you can read the output of the process using the process’s input stream. Here’s an example:

String command = "C:\\Windows\\System32\\cmd.exe /c dir"; ProcessBuilder pb = new ProcessBuilder(command); Process process = pb.start(); BufferedReader reader = new BufferedReader(new InputStreamReader(process.getInputStream())); String line; while ((line = reader.readLine()) != null)

In this example, the output of the «dir» command is printed to the console.

That’s it! By specifying the full path of the program you want to run, you can avoid the «java.io.IOException: Cannot run program» error in Java.

Method 3: Add the location of the program to PATH environment variable

To fix the «java.io.IOException: Cannot run program «dir»: CreateProcess error=2, Das System?» error in Java, you can add the location of the program to the PATH environment variable. Here are the steps to do it:

1. Find the location of the program that you want to run. In this case, «dir» is a command-line tool that is included in Windows, so the location is usually «C:\Windows\System32».
2. Open the Control Panel and go to System > Advanced system settings > Environment Variables.
3. Under System Variables, find the «Path» variable and click «Edit».
4. Click «New» and add the location of the program that you found in step 1.
5. Click «OK» to close all the windows.

Here is an example Java code that demonstrates how to run the «dir» command:

import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; public class Main < public static void main(String[] args) < try < Process process = Runtime.getRuntime().exec("cmd /c dir"); BufferedReader reader = new BufferedReader(new InputStreamReader(process.getInputStream())); String line; while ((line = reader.readLine()) != null) < System.out.println(line); >reader.close(); > catch (IOException e) < e.printStackTrace(); >> >

In this code, we use the Runtime.getRuntime().exec() method to run the «cmd /c dir» command, which opens a command prompt and runs the «dir» command. Then, we use a BufferedReader to read the output of the command and print it to the console.

Note that we use «cmd /c» before the command to ensure that it is executed within a command prompt. This is necessary because the «dir» command is not an executable program, but a command that is built into the command prompt.

By adding the location of the «dir» command to the PATH environment variable, we ensure that the command can be found and executed by the Runtime.getRuntime().exec() method.

Method 4: Use ProcessBuilder.start() instead of Runtime.getRuntime().exec()

To fix the error «Java: how to fix java.io.IOException: Cannot run program «dir»: CreateProcess error=2, Das System?», you can use ProcessBuilder.start() instead of Runtime.getRuntime().exec(). Here’s how to do it:

ProcessBuilder builder = new ProcessBuilder("dir");

builder.directory(new File("C:\\Users\\username\\Documents"));

builder.redirectErrorStream(true);

Process process = builder.start();

InputStream inputStream = process.getInputStream(); BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream)); String line; while ((line = reader.readLine()) != null)  System.out.println(line); >

int exitCode = process.waitFor(); System.out.println("Exited with error code " + exitCode);

import java.io.BufferedReader; import java.io.File; import java.io.IOException; import java.io.InputStream; import java.io.InputStreamReader; public class ProcessBuilderExample  public static void main(String[] args) throws IOException, InterruptedException  ProcessBuilder builder = new ProcessBuilder("dir"); builder.directory(new File("C:\\Users\\username\\Documents")); builder.redirectErrorStream(true); Process process = builder.start(); InputStream inputStream = process.getInputStream(); BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream)); String line; while ((line = reader.readLine()) != null)  System.out.println(line); > int exitCode = process.waitFor(); System.out.println("Exited with error code " + exitCode); > >

Источник

How to fix «CreateProcess error=2, The system cannot find the file specified» even if the Path variable is specified (crossplatform)

I am trying to run a Maven build from within a Groovy script. It seems to not be able to find Maven though. I already checked the path variable and it contains the correct path. If I specifically execute mvn via C:/…/mvn.cmd it works. I now use System.getenv() which fixed the missing Java_home variable, but this doesn’t help with mvn. Weirdly enough commands like git … work without even specifying the environment. I also know that I could fix this by just opening a cmd and running the commands there but I cannot do this as it also has to run on a mac or linux machine.

File workingDir = new File(*MYWORKINGDIRECTORY*) def mvnbuild = 'mvn package'.execute(System.getenv().collect < k, v ->"$k=$v" >, workingdir) mvnbuild.waitForProcessOutput(System.out, System.err) 

2019-11-05 13:57:12.631 ERROR *MYSCRIPT* FAILED. Reason: java.io.IOException: Cannot run program "mvn" (in directory "C:\Users\*MYWORKINGDIRECTORY*"): CreateProcess error=2, The system cannot find the file specified 

def mvnbuild = 'where mvn'.execute(System.getenv().collect < k, v ->"$k=$v" >, workingdir) mvnbuild.waitForProcessOutput(System.out, System.err) 

C:\*THECORRECTMAVENPATH*\apache-maven-3.6.0\bin\mvn C:\*THECORRECTMAVENPATH*\apache-maven-3.6.0\bin\mvn.cmd 

Allthough it produces the same error as above if I try to run npm PS: I also checked System.getenv() , it contains the correct Maven path.

Источник