Hex to bin in java

Java Program to Convert Hexadecimal to Binary

This article is created to cover a program in Java that converts any hexadecimal number entered by user at run-time of the program to its equivalent binary value.

If you’re not aware about, how the hexadecimal to binary conversion takes place, then refer to Hexadecimal to Binary Conversion. Now let’s move on to the program.

Hexadecimal to Binary Conversion in Java

The question is, write a Java program to convert hexadecimal number to binary. The hexadecimal number must be received by user at run-time. The program given below is its answer:

import java.util.Scanner; public class CodesCracker < public static void main(String[] args) < int i=0, len; String hexadecimal; Scanner s = new Scanner(System.in); System.out.print("Enter the Hexadecimal Number: "); hexadecimal = s.nextLine(); len = hexadecimal.length(); char[] hexDigit = hexadecimal.toCharArray(); System.out.print("\nEquivalent Binary Value red">while(iswitch(hexDigit[i]) < case '0': System.out.print("0000"); break; case '1': System.out.print("0001"); break; case '2': System.out.print("0010"); break; case '3': System.out.print("0011"); break; case '4': System.out.print("0100"); break; case '5': System.out.print("0101"); break; case '6': System.out.print("0110"); break; case '7': System.out.print("0111"); break; case '8': System.out.print("1000"); break; case '9': System.out.print("1001"); break; case 'a': case 'A': System.out.print("1010"); break; case 'b': case 'B': System.out.print("1011"); break; case 'c': case 'C': System.out.print("1100"); break; case 'd': case 'D': System.out.print("1101"); break; case 'e': case 'E': System.out.print("1110"); break; case 'f': case 'F': System.out.print("1111"); break; default: System.out.println("\nInvalid Hexadecimal Digit!"); return; > i++; > > >

The sample run of above program with user input 12A as hexadecimal number to convert and print its equivalent binary value, is shown in the snapshot given below:

Note — The toCharArray() method converts string to character array. And length() method used in above program, to find the length of the string stored in hexadecimal variable using hexadecimal.length() .

Since in previous program, I’ve directly checked the hexadecimal digit, and printed the equivalent binary value, one by one. Therefore, let’s modify the above program in a way to store the binary value in a variable say binary first, then print the equivalent binary value, using single System.out.print() or System.out.println() statement.

import java.util.Scanner; public class CodesCracker < public static void main(String[] args) < int i=0, len; String hexadecimal, binary=""; Scanner s = new Scanner(System.in); System.out.print("Enter the Hexadecimal Number: "); hexadecimal = s.nextLine(); len = hexadecimal.length(); char[] hexDigit = hexadecimal.toCharArray(); while(iswitch(hexDigit[i]) < case '0': binary += "0000"; break; case '1': binary += "0001"; break; case '2': binary += "0010"; break; case '3': binary += "0011"; break; case '4': binary += "0100"; break; case '5': binary += "0101"; break; case '6': binary += "0110"; break; case '7': binary += "0111"; break; case '8': binary += "1000"; break; case '9': binary += "1001"; break; case 'a': case 'A': binary += "1010"; break; case 'b': case 'B': binary += "1011"; break; case 'c': case 'C': binary += "1100"; break; case 'd': case 'D': binary += "1101"; break; case 'e': case 'E': binary += "1110"; break; case 'f': case 'F': binary += "1111"; break; default: System.out.println("\nInvalid Hexadecimal Digit!"); return; > i++; > System.out.println("\nEquivalent Binary Value program_box"> 
binary += "0000";
 
Same Program in Other Languages
 
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How to convert hex to binary in java
 
That way, the string will be guaranteed to be 9 characters long, and then you can just shave off the first character using : Solution 2: Hint: use string concatenation to add the appropriate number of zeros in the appropriate place. Solution 1: To Be clear: Solution 2: You can always do a static lookup: Solution 3: simply use a to determine the number of missing zeros:
 
Conversion from hex to binary keeping 8 bits in Java
 
 
My question is: is there a function to convert to binary in an 8-bit format (filling the left positions with zeros)?
 
 
No, there isn't. You have to write it yourself.
 
Here's one simple way. If you know the input is always a single byte, then you could add 256 to the number before calling toBinaryString . That way, the string will be guaranteed to be 9 characters long, and then you can just shave off the first character using substring :
 
String bin = Integer.toBinaryString(256 + i).substring(1); 
 
Hint: use string concatenation to add the appropriate number of zeros in the appropriate place.
 
public String hexToBin(String hex) throws NumberFormatException
 
I've concatenated this way. Thanks!
 
private String hexToBin (String hex) < int i = Integer.parseInt(hex, 16); String bin = Integer.toBinaryString(i); while (bin.length()<8)< bin="0"+bin; >return bin; > 
 
Convert Hex to Binary at android, use. String HexToBinary(String Hex) < String bin = new BigInteger(Hex, 16).toString(2); int inb = Integer.
 
Hexadecimal to binary in java
 
 
 
Hexadecimal to Decimal Binary and Octal i java programming
 
This video is about transfer from Hexadecimal to Decimal Binary and Octal You can also Duration: 3:48
 
 
 
Converting hex to binary with leading zeros
 
You can pad with spaces using String.format("%64s") and then replace spaces with zeros. This has the advantage of working for any size of input, not just something in the int range. I'm guessing you're working with arbitrary inputs from your use of BigInteger.
 
String value = new BigInteger("3031323334353637", 16).toString(2); System.out.println(String.format("%64s", value).replace(" ", "0")); 
 
0011000000110001001100100011001100110100001101010011011000110111 
 
Explanation. The String.format("%64s, value) outputs the earlier String padded to fill 64 characters.
 
" 11000000110001001100100011001100110100001101010011011000110111" 
 
The leading spaces are then replaced with '0' characters using String.replace(oldString, newString)
 
"0011000000110001001100100011001100110100001101010011011000110111" 
 
The following may be the easiest:
 
new BigInteger("1" + str,16).toString(2).substring(1)
 
You can do it using String.format() :
 
String unpaddedBinary = new BigInteger("a12", 16).toString(2); String paddedBinary = String.format("%064s", Integer.parseInt(unpaddedBinary, 2)); 
 
Convert a string representation of a hex dump to a byte array using, String hex = "0001027f80fdfeff"; byte[] converted = IntStream.range(0, hex.length() / 2) .map(i -> Character.digit(hex.charAt(i
 
Converting from hex to binary and binary to hex, without using conversion, reading txt file to find errors in RAM
 
OK, your question was unclear to me. The reason that you get only one number is that you call from main to hexToBinary , loop thru the entire file with this method, and then return to main . After that, you call to binaryToDecimal which prints out the value of result , which is the last value it got from hexToBinary . 
What you need to do is to read a value from the file, convert it to binary and then to decimal and proceed to the next value. One way of doing it is this: 
Change your methods to return a value and to get a parameter. 
hexToBinary should be -
 
public static String hexToBinary(String hex) throws IOException < String result = ""; String binVal; // the binary value of the Hex for (int i = 0; i < hex.length(); i++) < char hexChar = hex.charAt(i); switch (hexChar) < case ('0'): binVal = "0000"; break; case ('1'): binVal = "0001"; break; case ('2'): binVal = "0010"; break; case ('3'): binVal = "0011"; break; case ('4'): binVal = "0100"; break; case ('5'): binVal = "0101"; break; case ('6'): binVal = "0110"; break; case ('7'): binVal = "0111"; break; case ('8'): binVal = "1000"; break; case ('9'): binVal = "1001"; break; case ('A'): binVal = "1010"; break; case ('B'): binVal = "1011"; break; case ('C'): binVal = "1100"; break; case ('D'): binVal = "1101"; break; case ('E'): binVal = "1110"; break; case ('F'): binVal = "1111"; break; default: binVal = "invalid input"; break; >result += binVal; > return result; > 
 
binaryToDecimal should be -
 
public static Double binaryToDecimal(String result) < double j=0; for(int i=0;i> return j; > 
 
And the main will read the file, pass the values to both methods and print the result:
 
 public static void main(String args[]) throws IOException
 
 
Binary of ABCDEFABC:101010111100110111101111101010111100 Decimal value: 4.6118402748E10 Binary of 1A00D0000:000110100000000011010000000000000000 Decimal value: 6.980173824E9 Binary of 7A0EDF301:011110100000111011011111001100000001 Decimal value: 3.2764719873E10 Binary of 3CDAEFFAD:001111001101101011101111111110101101 Decimal value: 1.6335699885E10
 
 
Hope this is helpful for you.
 
Convert hex string to binary string, You need to tell Java that the int is in hex, like this: String hexToBinary(String hex) < int i = Integer.parseInt(hex, 16); String bin
 
Efficiently converting hex to binary
 
String.format("%04d", yournumber); 
 
public static String HexToBinary(char Hex)
 
You can always do a static lookup:
 
private static String[] staticLookup = new String[] ; public static String HexToBinary(char Hex)
 
simply use a switch to determine the number of missing zeros:
 
Java Program to Convert Hex String to Byte Array, Another way to convert a hex string to a byte array is to use the Binary shift operators of Java. Here “
 
Источник
 
Java Program to Convert Hexadecimal to Binary
 
The Hexadecimal is a very useful Number System based on the premise of clubbing together 4 bits at a time to constitute a single entity of the system which is composed of 16 symbols including 10 digits ranging from 0-9 and the first six alphabets from A-F. The word Hexadecimal is derived from the words Hex which means six and decimal which means ten.
 
Thus the combined word denotes sixteen which is six and ten added together. The Hexadecimal Sequences are also referred to as the base or radix 16. While dealing with different Number Systems, it becomes essential to be able to convert them from one system to another. In this article, we focus on converting Hexadecimal to Binary, which is a system comprised of 1’s and 0’s and is the mechanism through which the computers store and process instructions as well as data.
 
Hexadecimal Sequence : 458A Binary Equivalent : 0100010110001010 Explanation : Binary representation of A : 1010 Binary representation of 8 : 1000 Binary representation of 5 : 0101 Binary representation of 4 : 0100 Hexadecimal Sequence : B36 Binary Equivalent : 101100110110
 
 
There are two approaches to convert Hexadecimal to Binary and they are mentioned as follows :
 
 
Using the key-value pair for the corresponding conversion from the Hexadecimal character to its Binary equivalent
 
Converting the Hexadecimal to its Decimal equivalent which is further converted to its Binary equivalent
 
 
Approach 1 :
 
Using this approach, we formulate key-value and extracting every character of the Hexadecimal string, add its corresponding binary sequence and return the complete binary sequence.
 
 
Create a HashMap to store the key-value pairs.
 
Accept the Hexadecimal sequence as a string and extract each character while iterating through the length of the string.
 
Check if the extracted character is present in the keys of the HashMap.
 
If it is present, concatenate the string storing the binary sequence with the corresponding value of the key.
 
If it is not present, return Invalid Hexadecimal String.
 
 
Источник
 
Java: Convert a hexadecimal to a binary number
 
Write a Java program to convert a hexadecimal number into a binary number.
 
Hexadecimal number: This is a positional numeral system with a radix, or base, of 16. Hexadecimal uses sixteen distinct symbols, most often the symbols 0-9 to represent values zero to nine, and A, B, C, D, E, F (or alternatively a, b, c, d, e, f) to represent values ten to fifteen.
 
Binary number: A binary number is a number expressed in the base-2 numeral system or binary numeral system. This system uses only two symbols: typically 1 (one) and 0 (zero).
 
Test Data: 
Input any hexadecimal number: 37
 
Pictorial Presentation: Hexadecimal to Binary number
 
 
 
Sample Solution:
 
import java.util.Scanner; public class Exercise29 < public static int hex_to_decimal(String s) < String digits = "0123456789ABCDEF"; s = s.toUpperCase(); int val = 0; for (int i = 0; i < s.length(); i++) < char c = s.charAt(i); int d = digits.indexOf(c); val = 16*val + d; >return val; > public static void main(String args[]) < String hexdec_num; int dec_num, i=1, j; int bin_num[] = new int[100]; Scanner scan = new Scanner(System.in); System.out.print("Enter Hexadecimal Number : "); hexdec_num = scan.nextLine(); /* convert hexadecimal to decimal */ dec_num = hex_to_decimal(hexdec_num); /* convert decimal to binary */ while(dec_num != 0) < bin_num[i++] = dec_num%2; dec_num = dec_num/2; >System.out.print("Equivalent Binary Number is: "); for(j=i-1; j>0; j--) < System.out.print(bin_num[j]); >System.out.print("\n"); > > 
 
Enter Hexadecimal Number : 37 Equivalent Binary Number is: 110111
 
 
 
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