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Find project path in java

Содержание
  1. PATH and CLASSPATH
  2. Update the PATH Environment Variable (Microsoft Windows)
  3. Update the PATH Variable (Solaris and Linux)
  4. Checking the CLASSPATH variable (All platforms)
  5. [java] How to locate the Path of the current project directory in Java (IDE)?
  6. The answer is
  7. YOU CANT.

PATH and CLASSPATH

This section explains how to use the PATH and CLASSPATH environment variables on Microsoft Windows, Solaris, and Linux. Consult the installation instructions included with your installation of the Java Development Kit (JDK) software bundle for current information.

After installing the software, the JDK directory will have the structure shown below.

The bin directory contains both the compiler and the launcher.

Update the PATH Environment Variable (Microsoft Windows)

You can run Java applications just fine without setting the PATH environment variable. Or, you can optionally set it as a convenience.

Set the PATH environment variable if you want to be able to conveniently run the executables ( javac.exe , java.exe , javadoc.exe , and so on) from any directory without having to type the full path of the command. If you do not set the PATH variable, you need to specify the full path to the executable every time you run it, such as:

C:\Java\jdk1.7.0\bin\javac MyClass.java

The PATH environment variable is a series of directories separated by semicolons ( ; ). Microsoft Windows looks for programs in the PATH directories in order, from left to right. You should have only one bin directory for the JDK in the path at a time (those following the first are ignored), so if one is already present, you can update that particular entry.

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The following is an example of a PATH environment variable:

C:\Java\jdk1.7.0\bin;C:\Windows\System32\;C:\Windows\;C:\Windows\System32\Wbem

It is useful to set the PATH environment variable permanently so it will persist after rebooting. To make a permanent change to the PATH variable, use the System icon in the Control Panel. The precise procedure varies depending on the version of Windows:

  1. Select Start, select Control Panel. double click System, and select the Advanced tab.
  2. Click Environment Variables. In the section System Variables, find the PATH environment variable and select it. Click Edit. If the PATH environment variable does not exist, click New .
  3. In the Edit System Variable (or New System Variable) window, specify the value of the PATH environment variable. Click OK. Close all remaining windows by clicking OK.
  1. From the desktop, right click the My Computer icon.
  2. Choose Properties from the context menu.
  3. Click the Advanced tab (Advanced system settings link in Vista).
  4. Click Environment Variables. In the section System Variables, find the PATH environment variable and select it. Click Edit. If the PATH environment variable does not exist, click New .
  5. In the Edit System Variable (or New System Variable) window, specify the value of the PATH environment variable. Click OK. Close all remaining windows by clicking OK.
  1. From the desktop, right click the Computer icon.
  2. Choose Properties from the context menu.
  3. Click the Advanced system settings link.
  4. Click Environment Variables. In the section System Variables, find the PATH environment variable and select it. Click Edit. If the PATH environment variable does not exist, click New .
  5. In the Edit System Variable (or New System Variable) window, specify the value of the PATH environment variable. Click OK. Close all remaining windows by clicking OK.
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Note: You may see a PATH environment variable similar to the following when editing it from the Control Panel:

%JAVA_HOME%\bin;%SystemRoot%\system32;%SystemRoot%;%SystemRoot%\System32\Wbem

Variables enclosed in percentage signs ( % ) are existing environment variables. If one of these variables is listed in the Environment Variables window from the Control Panel (such as JAVA_HOME ), then you can edit its value. If it does not appear, then it is a special environment variable that the operating system has defined. For example, SystemRoot is the location of the Microsoft Windows system folder. To obtain the value of a environment variable, enter the following at a command prompt. (This example obtains the value of the SystemRoot environment variable):

Update the PATH Variable (Solaris and Linux)

You can run the JDK just fine without setting the PATH variable, or you can optionally set it as a convenience. However, you should set the path variable if you want to be able to run the executables ( javac , java , javadoc , and so on) from any directory without having to type the full path of the command. If you do not set the PATH variable, you need to specify the full path to the executable every time you run it, such as:

% /usr/local/jdk1.7.0/bin/javac MyClass.java

To find out if the path is properly set, execute:

This will print the version of the java tool, if it can find it. If the version is old or you get the error java: Command not found, then the path is not properly set.

To set the path permanently, set the path in your startup file.

For C shell ( csh ), edit the startup file (~/.cshrc ):

set path=(/usr/local/jdk1.7.0/bin $path)

For bash , edit the startup file ( ~/.bashrc ):

PATH=/usr/local/jdk1.7.0/bin:$PATH export PATH

For ksh , the startup file is named by the environment variable, ENV . To set the path:

PATH=/usr/local/jdk1.7.0/bin:$PATH export PATH

For sh , edit the profile file ( ~/.profile ):

PATH=/usr/local/jdk1.7.0/bin:$PATH export PATH

Then load the startup file and verify that the path is set by repeating the java command:

% source ~/.cshrc % java -version

Checking the CLASSPATH variable (All platforms)

The CLASSPATH variable is one way to tell applications, including the JDK tools, where to look for user classes. (Classes that are part of the JRE, JDK platform, and extensions should be defined through other means, such as the bootstrap class path or the extensions directory.)

The preferred way to specify the class path is by using the -cp command line switch. This allows the CLASSPATH to be set individually for each application without affecting other applications. Setting the CLASSPATH can be tricky and should be performed with care.

The default value of the class path is «.», meaning that only the current directory is searched. Specifying either the CLASSPATH variable or the -cp command line switch overrides this value.

To check whether CLASSPATH is set on Microsoft Windows NT/2000/XP, execute the following:

On Solaris or Linux, execute the following:

If CLASSPATH is not set you will get a CLASSPATH: Undefined variable error (Solaris or Linux) or simply %CLASSPATH% (Microsoft Windows NT/2000/XP).

To modify the CLASSPATH , use the same procedure you used for the PATH variable.

Class path wildcards allow you to include an entire directory of .jar files in the class path without explicitly naming them individually. For more information, including an explanation of class path wildcards, and a detailed description on how to clean up the CLASSPATH environment variable, see the Setting the Class Path technical note.

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[java] How to locate the Path of the current project directory in Java (IDE)?

I am trying to locate the path of the current running/debugged project programmatically in Java, I looked in Google and what I found was System.getProperty(«user.id») , which didn’t get me the project’s path.

I know the command Environment.currentDirectory in C# gives the path of the current running/debugged project,so I am sure there must be a similar way in Java, too.

So I am asking if anyone could tell me or give me a code to how locate the path of the currently running/debugged project programmatically?

edit: i am writing plugin which loads with eclipse start. the plugin adds a button to the workbench of eclipse, with in the code of the plugin when i click the button i search for the current directory path.

my purpose is that when for example i debug a project and then click the button, a window will pop up presenting the debugged project’s path, thanks

This question is related to java eclipse path

The answer is

File currentDirFile = new File("."); String helper = currentDirFile.getAbsolutePath(); String currentDir = helper.substring(0, helper.length() - currentDirFile.getCanonicalPath().length());//this line may need a try-catch block

The idea is to get the current folder with «.», and then fetch the absolute position to it and remove the filename from it, so from something like

/home/shark/eclipse/workspace/project/src/com/package/name/bin/Class.class

when you remove Class.class you’d get

/home/shark/eclipse/workspace/project/src/com/package/name/bin/

which is kinda what you want.

Use user.dir key for get project location using java.

System.out.println("Present Project Directory : "+ System.getProperty("user.dir"));

Present Project Directory :C:\workspace\MyEclipse 10\examples\MySqlMavenDomain

For displaying all systems properties simply use System.getProperties();

Use Key value in System.getProperty(«java.version»); for get output.

Properties properties = System.getProperties(); Enumeration enumeration = properties.keys(); for (int i = 0; i < properties.size(); i++) < Object obj = enumeration.nextElement(); System.out.println("Key: "+obj+"\tOutPut http://docs.oracle.com/javase/7/docs/api/java/lang/System.html" rel="noreferrer">Class System

What about System.getProperty("user.dir")? It'll give you the working directory from where your program was launched.

See System Properties from the Java Tutorial for an overview of Java's System Properties.

This is the new way to do it:

Path root = FileSystems.getDefault().getPath("").toAbsolutePath(); Path filePath = Paths.get(root.toString(),"src", "main", "resources", fileName); 
Path root = Paths.get(".").normalize().toAbsolutePath();

But I would take it one step further:

public String getUsersProjectRootDirectory() < String envRootDir = System.getProperty("user.dir"); Path rootDIr = Paths.get(".").normalize().toAbsolutePath(); if ( rootDir.startsWith(envRootDir) ) < return rootDir; >else < throw new RuntimeException("Root dir not found in user directory."); >>

YOU CANT.

Java-Projects does not have ONE path! Java-Projects has multiple pathes even so one Class can have multiple locations in different classpath's in one "Project".

So if you have a calculator.jar located in your JRE/lib and one calculator.jar with the same classes on a CD: if you execute the calculator.jar the classes from the CD, the java-vm will take the classes from the JRE/lib!

This problem often comes to programmers who like to load resources deployed inside of the Project. In this case,

System.getResource("/likebutton.png")

you can get the current project path use System.getProperty("user.dir")

in that method you write Key name to get your different-different paths, and if you don't know key, you can find all property use of System.getProperties() this method is return all property with key. and you can find key name manually from it.

and write System.getProperty("KEY NAME")

and get your require path.

File currDir = new File("."); String path = currDir.getAbsolutePath(); System.out.println(path);

This will print . at the end. To remove, simply truncate the string by one char e.g.:

File currDir = new File("."); String path = currDir.getAbsolutePath(); path = path.substring(0, path.length()-1); System.out.println(path);

This is a code snippet to retrieve the path of the current running web application project in java.

public String getPath() throws UnsupportedEncodingException < String path = this.getClass().getClassLoader().getResource("").getPath(); String fullPath = URLDecoder.decode(path, "UTF-8"); String pathArr[] = fullPath.split("/WEB-INF/classes/"); System.out.println(fullPath); System.out.println(pathArr[0]); fullPath = pathArr[0]; return fullPath; >
System.out.println(System.getenv().get("PWD"));

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