- 3 Tips to solve and Avoid java.lang.ArrayindexOutOfBoundsException: 1 in Java Programs — Example
- Understanding ArrayIndexOutOfBoundsException
- How to avoid ArrayIndexOutOfBoundsException in Java
- Ошибка ArrayIndexOutOfBoundsException Java
- [Solved] ArrayIndexOutOfBoundException in JAVA
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3 Tips to solve and Avoid java.lang.ArrayindexOutOfBoundsException: 1 in Java Programs — Example
The error ArrayIndexOutOfBoundsException : 1 means index 1 is invalid and it’s out of bounding i.e. more than the length of the array. Since the array has a zero-based index in Java, this means you are trying to access the second element of an array which only contains one element. The ArrayIndexOutfBoundsException comes when your code, mostly for loop tries to access an invalid index of the array. If you have worked in C, C++ then you will notice this difference between array in C and Java. You simply cannot access invalid array index in Java i.e. indexes which are less than zero and more than the length of the array.
ArrayIndexOutOfBounds is also a subclass of IndexOutOfBoundsException which is used to throw an error related to an invalid index e.g. try to access outside of length in String etc.
An array is a data structure that is the base for many advanced data structures e.g. list, hash table or a binary tree. The array stores elements in the contiguous memory location and it can also have multiple dimensions e.g. a two-dimensional array. You can use the 2D array to represent a matrix, a board in games like Tetris, Chess, and other board games.
Also, knowledge of data structure and the algorithm is a must for any good programmer. You can also join these free data structure and algorithms courses to learn more about an array in Java.
Understanding ArrayIndexOutOfBoundsException
This error comes when you are accessing or iterating over an array directly or indirectly. Directly means you are dealing with array type e.g. String[] or main method, or an integer[] you have created in your program. Indirectly means via Collection classes that internally use an array e.g. ArrayList or HashMap.
Now let’s understand what information the associated error message gives us:
java.lang.ArrayIndexOutOfBoundsException: 0 means you are trying to access index 0 which is invalid, which in turn means the array is empty.
Here is a Java program that reproduces this error by accessing the first element of the empty array i.e. array with zero length:
public class HelloWorldApp < public static void main(String args[]) < // reproducing java.lang.ArrayIndexOutOfBoundsException : 0 error String[] names = new String[0]; String name = names[0]; // this will throw java.lang.ArrayIndexOutOfBoundsException : 0 System.out.println(name); > > Output Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0 at beginner.HelloWorldApp.main(HelloWorldApp.java:21)
You can see the accessing first element of an empty array resulted in the ArrayIndexOutOfBoundsException in Java.
java.lang.ArrayindexOutOfBoundsException: 1 means index 1 is invalid, which in turn means the array contains just one element. Here is a Java program that will throw this error:
public class HelloWorldApp < public static void main(String args[]) < // reproducing java.lang.ArrayIndexOutOfBoundsException : 1 error String[] languages = "Java">; String language = languages[1]; // this will throw java.lang.ArrayIndexOutOfBoundsException : 1 System.out.println(language); > > When you run this program it will throw following error: Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 1 at beginner.HelloWorldApp.main(HelloWorldApp.java:17)
Similarly, java.lang.ArrayIndexOutOfBoundsException: 2 means index 2 is invalid, which means the array has just 2 elements and you are trying to access the third element of the array.
Sometimes when a programmer makes a switch from C/C++ to Java they forget that Java does the bound checking at runtime, which is a major difference between C++ and Java Array. You should also join these Java Programming and development courses if you are learning Java and knows C++. The author often highlights the key difference between C++ and Java while teaching important concepts.
How to avoid ArrayIndexOutOfBoundsException in Java
In order to avoid the java.lang.ArrayIndexOutOfBoundsException, you should always do the bound check before accessing array element e.g.
if (args.length < 2) < System.err.println("Not enough arguments received."); return; >
Always remember that the array index starts at 0 and not 1 and an empty array has no element in it. So accessing the first element will give you the java.lang.ArrayIndexOutOfBoundsException : 0 error in Java.
You should always pay to one-off errors while looping over an array in Java. The programmer often makes mistakes that result in either missing the first or last element of the array by messing 1st element or finishing just before the last element by incorrectly using the , >= or operator in for loops.
For example, the following program will never print the last element of the array. The worst part is there won’t be any compile-time error or runtime exception. It’s a pure logical error that will cause incorrect calculation.
/** * Java Program to demonstrate one-off error while looping over array. * * @author WINDOWS 8 * */ public class HelloWorldApp < public static void main(String args[]) < int[] primes = ; for(int i = primes.length - 1; i > 0 ; i--)< System.out.println(primes[i]); > > > Output: 17 13 11 7 5 3
You can see the first element of the array i.e. 2 is never get printed. There is no compile-time or runtime error, though.
- Always remember that the array is a zero-based index, the first element is at the 0th index and the last element is at length — 1 index.
- Pay special attention to the start and end conditions of the loop.
- Beware of one-off errors like above.
And, here is a nice slide of some good tips to avoid ArrayIndexOutOfBondsException in Java:
That’s all about how to solve the java.lang.ArrayIndexOutOfBoundsException: 1 in Java. Always remember that the array uses the zero-based index in Java. This means the index of the first element in the array is zero and if an array contains only one element then the array[1] will throw java.lang.ArrayIndexOutOfBoundsException : 1 in Java. Similarly, if you try to access the first element of an empty array in Java, you will get the java.lang.ArrayIndexOutOfBoundsException : 0 error in Java.
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Thanks for reading this article so far. If you are getting ArrayIndexOutOfBoundException in your Java Program and not able to solve it then feel free to commit your code and exception here and I can take a look.
Ошибка ArrayIndexOutOfBoundsException Java
ArrayIndexOutOfBoundsException – это исключение, появляющееся во время выполнения. Оно возникает тогда, когда мы пытаемся обратиться к элементу массива по отрицательному или превышающему размер массива индексу. Давайте посмотрим на примеры, когда получается ArrayIndexOutOfBoundsException в программе на Java.
Попробуйте выполнить такой код:
static int number=11; public static String[][] transactions=new String[8][number]; public static void deposit(double amount) < transactions[4][number]="deposit"; number++; >public static void main(String[] args) < deposit(11); >>
Caused by: java.lang.ArrayIndexOutOfBoundsException: 0 at sample.Main.deposit(Main.java:22) at sample.Main.main(Main.java:27) Exception running application sample.Main Process finished with exit code 1
Что здесь произошло? Ошибка в строке 27 – мы вызвали метод deposit(), а в нем уже, в строке 22 – попытались внести в поле массива значение «deposit». Почему выкинуло исключение? Дело в том, что мы инициализировали массив размера 11 (number = 11), н опопытались обратиться к 12-му элементу. Нумерация элементов массива начинается с нуля. Так что здесь надо сделать, например, так
public static String[][] transactions=new String[8][100];
Но вообще, это плохой код, так писать не надо. Давайте рассмотрим еще один пример возникновения ошибки ArrayIndexOutOfBoundsException:
public static void main(String[] args) < Random random = new Random(); int [] arr = new int[10]; for (int i = 0; i >
Здесь массив заполняется случайными значениями. При выполнении IntelliJ IDEA выдаст ошибку
Caused by: java.lang.ArrayIndexOutOfBoundsException: 10 at sample.Main.main(Main.java:37)
В строке 37 мы заносим значение в массив. Ошибка возникла помтому, что индекса 10 нет в массиве arr, поэтому условие цикла i <= arr.length надо поменять на i < arr.length
Конструкция try для ArrayIndexOutOfBoundsException
ArrayIndexOutOfBoundsException можно обработать с помощью конструкции try-catch. Для этого оберните try то место, где происходит обращение к элементу массива по индексу, например, заносится значение. Как-то так:
try < array[index] = "что-то"; >catch (ArrayIndexOutOfBoundsException ae)
Но я бы рекомендовал вам все же не допускать данной ошибки, писать код таким образом, чтобы не пришлось ловить исключение ArrayIndexOutOfBoundsException.
Автор этого материала — я — Пахолков Юрий. Я оказываю услуги по написанию программ на языках Java, C++, C# (а также консультирую по ним) и созданию сайтов. Работаю с сайтами на CMS OpenCart, WordPress, ModX и самописными. Кроме этого, работаю напрямую с JavaScript, PHP, CSS, HTML — то есть могу доработать ваш сайт или помочь с веб-программированием. Пишите сюда.
заметки, ArrayIndexOutOfBoundsException, java, ошибки, исключения
[Solved] ArrayIndexOutOfBoundException in JAVA
java.lang.ArrayindexOutOfboundsException is Runtime and Unchecked Exception. It’s subclass of java.lang IndexOutOfBoundsException.
ArrayIndexOutOfBoundsException is most common error in Java Program. It throws when an array has been accessed with an illegal index either negative or greater than or equal to the size of the array.
- Array index starts at zero and goes to length – 1, for example in an integer array int[] counts= new int[20], the first index would be zero and last index out be 19 (20 -1)
- Array index cannot be negative, hence counts[-1] will throw java.lang.ArrayIndexOutOfBoundsException.
- The maximum array index can be Integer.MAX_VALUE -1 because array accept data type of index is int and max allowed value for int is Integer.MAX_VALUE.
Constructors:
- ArrayIndexOutOfBoundsException() : Constructs an ArrayIndexOutOfBoundsException with no detail message.
- ArrayIndexOutOfBoundsException(int index) : Constructs a new ArrayIndexOutOfBoundsException class with an argument indicating the illegal index.
- ArrayIndexOutOfBoundsException(String s) : Constructs an ArrayIndexOutOfBoundsException class with the specified detail message.
public class ArrayOutOfBoundException < public static void main(String[] args) < String [] empArr=; //No of employee in array //Will through IndexOuhtOfBoundException because array having only six element of index 0 to 5 try < String name=empArr[8]; System.out.println("Employee :"+empArr[8]); >catch(ArrayIndexOutOfBoundsException ex) < ex.printStackTrace(); >> > java.lang.ArrayIndexOutOfBoundsException: 8 at example.ArrayIndexOutOfBoundsException.main(ArrayIndexOutOfBoundsException.java:11)