Deprecated api error in java

It is considered a bad practice to add @SuppressWarnings("deprecation") annotation to tell the compiler to "be quiet" about it because in the future the deprecated API may be removed and that will prevent your code from running when you upgrade.

If you implement any of the two solutions then you will no longer be receiving the warning message.

That's all for today. Please mention in the comments in case you have any questions related to warning java uses or overrides a deprecated api. recompile with -Xlint:deprecation for details.

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Subham Mittal has worked in Oracle for 3 years.
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Fix the Warning: Uses or Overrides a Deprecated API in Java

Today, we will see why a warning says uses or overrides a deprecated API and demonstrate how to fix this to accomplish the task.

Fix Warning Saying uses or overrides a deprecated API in Java

Example Code (that contains a warning):

//import libraries  import java.io.BufferedInputStream; import java.io.DataInputStream; import java.io.File; import java.io.FileInputStream; import java.io.IOException;  //Main class  public class Main    //main method  public static void main(String[] args)  //path of a text file  File filePath = new File("Files/TestFile.txt");  try   //obtain input bytes from a file  FileInputStream fileInputStream = new FileInputStream(filePath);  //adds the functionality to another input stream  BufferedInputStream bufferedInputStream = new BufferedInputStream(fileInputStream);  //lets an app read primitive Java data types from the specified input stream  DataInputStream dataInputStream = new DataInputStream(bufferedInputStream);   if (dataInputStream.available() != 0)   // Get a line.  String line = dataInputStream.readLine();  // Place words to an array which are split by a "space".  String[] stringParts = line.split(" ");  // Initialize the word's maximum length.  int maximumLength = 1;   // iterate over each stingPart, the next one is addressed as "stringX"  for (String stringX : stringParts)   // If a document contains the word longer than.  if (maximumLength  stringX.length())  // Set the new value for the maximum length.  maximumLength = stringX.length();  >//end for-loop   // +1 because array index starts from "0".  int[] counter = new int[maximumLength + 1];  for (String str : stringParts)   // Add one to the number of words that length has  counter[str.length()] ++;  >  // We are using this kind of loop because we require the "length".  for (int i = 1; i  counter.length; i++)   System.out.println(i + " letter words: " + counter[i]);  >//end for-loop  >//end if statement  >//end try  catch (IOException ex)  ex.printStackTrace();  >//end catch  >//end main method  >//end Main class 

In this code, we access a .txt file, read that file line by line and place the words in an array which are split based on a single space . Then, we count the number of characters in each word and display all of them in the program output.

Though this program generates the output, it also highlights that we are using or overriding a deprecated API at line String line = dataInputStream.readLine(); . See the following.

This warning is being generated using the readLine() method of the DataInputStream class. According to the documentation, this method has been deprecated since JDK 1.1 because it does not convert bytes to characters properly.

Although, the method is deprecated and likely will perform as expected in some cases. But we cannot guarantee that it will fulfill its job anymore.

Therefore, it is good to use a similar but consistent method.

As of JDK 1.1 , the method preferred for reading the lines of text is the readLine() function from the BufferedReader class. We don’t have to change all the code from scratch but only need to convert the DataInputStream to the BufferedReader class.

Replace this line of code:

DataInputStream dataInputStream = new DataInputStream(in); 

BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(in)); 

Now, the complete working program will look as follows.

//import libraries  import java.io.BufferedInputStream; import java.io.DataInputStream; import java.io.File; import java.io.FileInputStream; import java.io.IOException; import java.io.BufferedReader; import java.io.InputStreamReader;  //Main class  public class Main    //main method  public static void main(String[] args)  //path of a text file  File filePath = new File("Files/TestFile.txt");  try   //obtain input bytes from a file  FileInputStream fileInputStream = new FileInputStream(filePath);  //adds the functionality to another input stream  BufferedInputStream bufferedInputStream = new BufferedInputStream(fileInputStream);  //lets an app read primitive Java data types from the specified input stream  //DataInputStream dataInputStream = new DataInputStream(bufferedInputStream);  BufferedReader bufferedReader = new BufferedReader(  new InputStreamReader(bufferedInputStream));   String line="";  //get a line and check if it is not null  if ((line = bufferedReader. readLine()) != null)   // Place words to an array which are split by a "space".  String[] stringParts = line.split(" ");  // Initialize the word's maximum length.  int maximumLength = 1;   // iterate over each stingPart, the next one is addressed as "stringX"  for (String stringX : stringParts)   // If a document contains the word longer than.  if (maximumLength  stringX.length())  // Set the new value for the maximum length.  maximumLength = stringX.length();  >//end for-loop   // +1 because array index starts from "0".  int[] counter = new int[maximumLength + 1];  for (String str : stringParts)   // Add one to the number of words that length has  counter[str.length()] ++;  >  // We are using this kind of loop because we require the "length".  for (int i = 1; i  counter.length; i++)   System.out.println(i + " letter words: " + counter[i]);  >//end for-loop  >//end if statement  >//end try  catch (IOException ex)  ex.printStackTrace();  >//end catch  >//end main method  >//end Main class 

Additionally, if you also see something similar to the following.

Recompile with -Xlint: deprecation for details 

Don’t worry; it just tells you an option to use while compiling to have more details about where you are using the deprecated stuff.

Mehvish Ashiq is a former Java Programmer and a Data Science enthusiast who leverages her expertise to help others to learn and grow by creating interesting, useful, and reader-friendly content in Computer Programming, Data Science, and Technology.

Related Article - Java Warning

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[Fixed] uses or overrides a deprecated api. recompile with -xlint:deprecation for details.

What is warning message: uses or overrides a deprecated api

You will get this warning when you are using deprecated api in your code.

Example:
Let’s say you have simple swing code which displays a JFrame with JButton on it.

When you will compile the code, you will get below output:

C:\Users\Arpit\Desktop\javaPrograms>javac JFrameDeprecatedAPIExample.java
Note: JFrameDeprecatedAPIExample.java uses or overrides a deprecated API.
Note: Recompile with -Xlint:deprecation for details.

As you can see, compile gives us warning message that JFrameDeprecatedAPIExample.java uses or overrides a deprecated API.

We are getting this warning message because JFrame’s show() method is deprecated and should not be used.

If you want to know about deprecated API, you can use below command:

C:\Users\Arpit\Desktop\javaPrograms>javac JFrameDeprecatedAPIExample.java -Xlint:deprecation
JFrameDeprecatedAPIExample.java:18: warning: [deprecation] show() in Window has been deprecated
frame.show();
^
1 warning

💡 Did you know?

If you are using IDEs like eclipse or intellij, then it will show deprecated APIs with strike through.

If you are using maven, you can use -Dmaven.compiler.showDeprecation=true with maven goals.

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