- Using Mysqli bind_param with date and time columns?
- Filter Range Of Date With MySQL using PHP
- Getting Started:
- Creating Database
- Creating the database connection
- Creating The Interface
- PHP - Filter Range Of Date With MySQLi
- Creating the Main Function
- MySQL and PHP query date = $date problems
- How to compare two datetime in mysql query using php
- 3 Answers 3
Using Mysqli bind_param with date and time columns?
Timestamps in PHP are integers (the number of seconds from the UNIX epoch). An alternative to the above is to use an integer type date/time parameter, and the MySQL functions FROM_UNIXTIME and UNIX_TIMESTAMP
$stmt = $mysqli->prepare("INSERT INTO FOO (dateColumn) VALUES (FROM_UNIXTIME(?))"); $stmt->bind_param("i", $your_date_parameter); $stmt->execute();
The valid range of a timestamp is typically from Fri, 13 Dec 1901 20:45:54 GMT to Tue, 19 Jan 2038 03:14:07 GMT. (These are the dates that correspond to the minimum and maximum values for a 32-bit signed integer). However, before PHP 5.1.0 this range was limited from 01-01-1970 to 19-01-2038 on some systems (e.g. Windows).
For the current date/time you can use the MySQL standard routine. You do not have to prepare that.
$query = "INSERT INTO tablename "; $query .= "VALUES(. NOW()) "; $preparedquery = $dbaselink->prepare($query); $preparedquery->bind_param("iii",$val1,$val2,$val3);
I used the date( ) function and this solved me the problem.
$stmt = $mysqli->prepare("INSERT INTO FOO (dateColumn) VALUES ?"); // 6/10/2015 10:30:00 $datetime = date("Y-m-d H:i:s", mktime(10, 30, 0, 6, 10, 2015)); $stmt->bind_param("s", $datetime); $stmt->execute();
first set the date & time using date() function-
then pass it into the prepared statement, just like any other string variable-
$stmt = $mysqli->prepare("INSERT INTO FOO (dateColumn, timeColumn) VALUES (. )"); $stmt->bind_param("ss", $date , $time); $stmt->execute();
Filter Range Of Date With MySQL using PHP
In this tutorial, we will create a Filter Range Of Date With MySQLi using PHP. This code can filter a range of table row from MySQLi when the user provides two dates from inputs. The code use MySQLi SELECT query to filter a variety of data in the MySQL row by providing two dates in the WHERE clause by adding a parameter BETWEEN . This a user-friendly program feel free to modify and use it to your system.
We will be using PHP as a scripting language and interpreter that is mainly used on any web server, including xamp, wamp, etc. It is being applied to any popular websites because of the modern approach as its today.
Getting Started:
First, you have to download & install XAMPP or any local server that run PHP scripts. Here’s the link for XAMPP server https://www.apachefriends.org/index.html .
And, this is the link for the bootstrap that I used for the layout design https://getbootstrap.com/ .
Creating Database
Open your database web server then create a database name in it db_range , after that click Import then locates the database file inside the folder of the application then click ok.
Creating the database connection
Open your any kind of text editor(notepad++, etc..). Then just copy/paste the code below then name it conn.php.
Creating The Interface
This is where we will create a simple form for our application. To create the forms simply copy and write it into your text editor, then save it as index.php.
PHP - Filter Range Of Date With MySQLi
Firstname Lastname Project Date Submit
Creating the Main Function
This code contains the main function of the application. This code will filter a range of data when the button is clicked. To do that just copy and write this block of codes inside the text editor, then save it as range.php.
0) < while($fetch=mysqli_fetch_array($query))< ?>>else < echo' '; > >else < $query=mysqli_query($conn, "SELECT * FROM `member`") or die(mysqli_error()); while($fetch=mysqli_fetch_array($query))< ?> Record Not Found > ?> There you have it we successfully created Filter Range Of Date With MySQLi using PHP. I hope that this simple tutorial help you to what you are looking for. For more updates and tutorials just kindly visit this site. Enjoy Coding!
MySQL and PHP query date = $date problems
I’m having a simple problem with a query comparing a date in a table to a date input from a user. (give me a list of all people in the table with birthdate «MM/DD/YYYY»). When entering a new person into a db I want to verify that that person is not already in the db. So using «firstname» «lastname» and «date of birth» the table is queried and if there is a match, a window pops up and says «are you sure you want to do this — looks like the person is already entered». There is NO PROBLEM with «firstname» «lastname» (I’ve got that working nicely) so now I want to add «date of birth» to the query. As a start, I removed «firstname» and «lastname» and am only using «date of birth». As a «proof of concept» the following MySQL query works fine on the MySQL Workbench:
SET @testdate = "1934-06-06"; SELECT localid, firstname, lastname, dob FROM administrative WHERE dob = @testdate;
The «dob» column in the table is a «date» format not «datetime». So I now switch over to php and write this as a test:
$frontenddob = "06/06/1934"; $dob = date("Y-m-d", strtotime($frontenddob)); echo "--$frontenddob--
"; //gives 06/06/1934 echo "--$dob--
"; //gives --1934-06-06-- ("--" added to "see" extra spaces) echo "$dob"; echo "
"; //gives 1934-06-06 $host = "xx"; $user = "xx"; $password = "xx"; $dbname = "xx"; $cxn = mysqli_connect($host,$user,$password,$dbname); if (mysqli_connect_errno()) $query = " SELECT * FROM administrative WHERE dob = $dob ORDER BY lastname ASC ";
- The format in the table for dob (date of birth) is «date» not «datetime».
- The user input string date format is converted to MySQL date format YYYY-MM-DD.
- The query works with , =.
How to compare two datetime in mysql query using php
I want to compare two datetime variable witch one of them is current server time and one of them is stored in mysql database i am running this simple piece of code and it wont work and says it is a syntax error i am wondering what can i do
> start_date"; $result=mysqli_query($cnn,$query1); if($result)< $row=mysqli_fetch_array($result); echo $exam_id. "exists"; >else ?>
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ‘query1’ at line 1
3 Answers 3
$query1="select exam_id from exam where > start_date"; $result=mysqli_query($cnn,@query1); //
You are using @query1 , this should be $query1 .
yup that's it, additionally you have to be sure to have the mysql server using the same timezone as your apache/php one. The best is to configure in mysqld.ini and in php.ini the timezone so that it is using UTC
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '12:30:21' at line 1 @phantom
You should be using timestamps to compare date/time values. As stated in the answer by Raheel, you should be using start_date > '' (or <, no quotes req. if you're using timestamps) instead of > start_date .$now_date>
$query1="select exam_id from exam where > start_date"; $result=mysqli_query($cnn,@query1);
I think the error is because you are using @ insteal of $. Also your query seems to be wrong. You should compare values with fields change it to
$query1="select exam_id from exam where start_date > ''"; $result=mysqli_query($cnn,$query1);
Even if correct the misstype of @query1 the query will not work like this. $now_date is a string and you have to pass it to the query like a string. Even better if you format it with mysql's functions, not with php's one as well as compare time stored in database with database's own time (then you can skip any timezone problems). So, your query, for example, could be like this:
SELECT exam_id FROM exam WHERE DATEDIFF(NOW(), DATE_FORMAT(start_date,'%Y-%m-%d %T')) > 0;
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