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Java Convert String to XML DOM Example

To convert XML string to XML Dom, we need the following classes:

• javax.xml.parsers.DocumentBuilder : Defines the API to obtain XML DOM Document instances from XML content from various input sources. These input sources are InputStreams, Files, URLs, and SAX InputSources.
• javax.xml.parsers.DocumentBuilderFactory : Defines a factory API that enables applications to obtain a parser ( DocumentBuilder ) that produces DOM object trees from XML content.
• org.w3c.dom.Document : It represents the entire XML DOM. Conceptually, it is the root of the document tree, and provides the access to the document’s data further down into the tree, through factory methods.
• java.io.StringReader : Create a stream from String content. DocumentBuilder uses this stream to read XML content for parsing.

import java.io.StringReader; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.DocumentBuilderFactory; import org.w3c.dom.Document; import org.w3c.dom.Element; import org.w3c.dom.Node; import org.w3c.dom.NodeList; import org.xml.sax.InputSource; public class ConvertStringToXML < public static void main(String[] args) < final String xmlStr + " Lokesh Gupta" + " " + " " + " Brian Lara" + " " + " " + ""; //Use method to convert XML string content to XML Document object Document doc = convertStringToXMLDocument(xmlStr); //Verify XML document is build correctly System.out.println("Root Node : " + doc.getFirstChild().getNodeName()); NodeList nodeList = doc.getElementsByTagName("employee"); for (int itr = 0; itr < nodeList.getLength(); itr++) < Node node = nodeList.item(itr); System.out.println("\nNode Name : " + node.getNodeName()); if (node.getNodeType() == Node.ELEMENT_NODE) < Element eElement = (Element) node; System.out.println("Name: "+ eElement.getElementsByTagName("name").item(0).getTextContent()); System.out.println("Title: "+ eElement.getElementsByTagName("title").item(0).getTextContent()); >> > private static Document convertStringToXMLDocument(String xmlString) < //Parser that produces DOM object trees from XML content DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); //API to obtain DOM Document instance DocumentBuilder builder = null; try < //Create DocumentBuilder with default configuration builder = factory.newDocumentBuilder(); //Parse the content to Document object Document doc = builder.parse(new InputSource(new StringReader(xmlString))); return doc; >catch (Exception e) < e.printStackTrace(); >return null; > >

Root Node : employees Node Name : employee Name: Lokesh Gupta Title: Author Node Name : employee Name: Brian Lara Title: Cricketer

2. Convert XML File to XML Document

To get the XML dom from XML file, instead of passing the XML string to DocumentBuilder, pass the file path to let the parser read the file content directly.

We have employees.xml file which has XML content, we will read to get XML document.

  Lokesh Gupta   Brian Lara   

import java.io.File; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.DocumentBuilderFactory; import org.w3c.dom.Document; public class StringtoXMLExample < public static void main(String[] args) < final String xmlFilePath = "employees.xml"; //Use method to convert XML string content to XML Document object Document doc = convertXMLFileToXMLDocument( xmlFilePath ); //Verify XML document is build correctly System.out.println(doc.getFirstChild().getNodeName()); >private static Document convertXMLFileToXMLDocument(String filePath) < //Parser that produces DOM object trees from XML content DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance(); //API to obtain DOM Document instance DocumentBuilder builder = null; try < //Create DocumentBuilder with default configuration builder = factory.newDocumentBuilder(); //Parse the content to Document object Document doc = builder.parse(new File(filePath)); return doc; >catch (Exception e) < e.printStackTrace(); >return null; > >

Drop me your questions in the comments section.

Источник

Create source from string java

Representation of a source code unit and its contents that can be evaluated in an execution context . Each source is associated with the the ID of the language.

From a file on disk

Each file is represented as a canonical object, indexed by the absolute, canonical path name of the file. File content is read eagerly and may be optionally cached. Sample usage:

File file = new File(dir, name); assert name.endsWith(".java") : "Imagine proper file"; String language = Source.findLanguage(file); Source source = Source.newBuilder(language, file).build(); assert file.getName().equals(source.getName()); assert file.getPath().equals(source.getPath()); assert file.toURI().equals(source.getURI());

Read from an URL

URL resource = relativeClass.getResource("sample.js"); Source source = Source.newBuilder("js", resource) .build(); assert resource.toExternalForm().equals(source.getPath()); assert "sample.js".equals(source.getName()); assert resource.toURI().equals(source.getURI());

Each URL source is represented as a canonical object, indexed by the URL. Contents are read eagerly once the Source.Builder.build() method is called.

Source from a literal text

An anonymous immutable code snippet can be created from a string via the Source.newBuilder(String, java.lang.CharSequence, String) factory method:

Source source = Source.newBuilder("js", "function() + " return 'Hi';\n" + ">\n", "hi.js").buildLiteral(); assert "hi.js".equals(source.getName());

Reader stream = new InputStreamReader( relativeClass.getResourceAsStream("sample.js") ); Source source = Source.newBuilder("js", stream, "sample.js") .build(); assert "sample.js".equals(source.getName());

byte[] bytes = new byte[] ; Source source = Source.newBuilder("llvm", ByteSequence.create(bytes), "").buildLiteral();

public boolean isInteractive()

public boolean isInternal()