All exe files open with java

How to open an executable jar file

Solution: hh.exe can’t open files in a jar. So the actual command to execute a jar file, is meaning you call the java virtual machine with your jar file as a parameter.

How to open the executable file in this Java Project? I tried opening all the .jar files already

As others have said already, this jar is not a standalone App. It’s actually an client server application.

I took a quick look, you can exercise the client like this:

Assuming softquor.jar is in your current working directory.

In one console, start the server

java -cp softquor.jar softquor.Server 8080 

In another console start the Text client (you can start multiple clients!)

java -cp softquor.jar softquor.TextClient localhost 8080 

From the class name I do say the TextClient will let you enter some command and play the game. If you get something like ClassNotFoundException then it means the project is using some third party jar file. Unfortunately you will have to find out those dependencies yourself since there is no clear documentation on that.

I would assume the file in /dist/softquor.jar is the executable file.

You can explore contents of a JAR file just like any other zip files using a winzip. Inside you will find a /META-INF/ folder which will have the entry class.

From command prompt you can run it just like any other .jar file. Just make sure you use the full package name.

The softquor.jar isn’t executable. There is no Main-Class defined in the jar manifest. I looked around briefly and did not see an obvious main entry point that wasn’t in a test class. Though there was an a class that extended JApplet so you could possibly run the jar from a webpage using the java plugin.

Tough to tell as there appears to be no documentation for this project other than a short README file.

How to view the source code inside a JAR file?, Opening JAR files works with any software that supports the .ZIP file format, like WinRAR. But if you want to access the source code, it gets a little …

How to open an executable jar file (java)

The quality vid you’ve all been waiting for!Jokes aside, some people kept having troubles opening opsu!(d), and I couldn’t find a no-bullshit video, so I mad

How to Run Executable Java (.jar) Files in Windows

Here’s how to run executable Java (. jar ) files in Windows.- Get genuine Windows keys at 𝑷𝒓𝒊𝒎𝒆 𝑻𝒆𝒄𝒉 𝑴𝒂𝒓𝒕, links below: Windows 10 Pro key: http

How to open or run a JAR file on Windows

Learn more on https://www.thewindowsclub.com/how-to- open -or-run-a- jar — file -on-windowsTo view the reference video mentioned in this video, click on https://ww

How Open *.jar File? Is It the Same as .*exe for Windows?

1. jar is java archive. Unlike .exe it cannot be executed on the processor, but on the JVM. So the actual command to execute a jar file, is java -jar jarfilename meaning you call the java virtual machine with your jar file as a parameter.

You can do a double click to execute it, but the user will only see any result if you use a UI framework like Swing or AWT.

In your case, System.out.printlns and System.console().readLine() will be only interactable by the command console.

Yes, you can just double-click on your .jar to open it if java is installed and in your PATH, or run java -jar «jar_path» in cmd. Also, it’s not stopping because execution is done after your last instruction so it exits. I don’t remember the exact syntax but try reading a key from the user. It’ll pause your program until you press a key.

Edit: I think System.in.read(); is what you’re looking for.

How to make an executable jar file in java, You need to write jar then swiches then mf_file then jar_file then .classfile as given below: jar -cvmf myfile.mf myjar.jar First.class. jar -cvmf myfile.mf myjar.jar …

How to open help file in executable jar

hh.exe can’t open files in a jar. You need to either write some code copy the contents of Toolkit.getDefaultToolkit().getClass().getResource(«/resources/UserAcountHelpNew.chm») to a place on the file system, or distribute this file alongside the executable jar.

The reason it works in Eclipse is because you probably have the file on the file system. When your working directory changes, hh.exe can no longer find the file.

How can I convert a JAR file to an EXE file?, 0. 1) To create the exe, you can use Launch4j. 2) As I have seen, you cannot encrypt the jar contents. I’m not sure though. 3) To create the installer you can use the …

Unable to open executable jar file

java -cp name.jar Classname 

and check for errors at the command prompt.

If your program requires some external libraries, you can mention them inside the manifest file.

Class-Path: lib/file1.jar lib/file2.jar 

where lib is in the same directory where the jar file is.

Java — How to make my jar file executable by double click, To make a jar file executable you have to set the entrypoint. You can do this by passing the e option to the jar command when you create the jar …

Источник

Executing a .exe Program with Java

I have a code example that needs to be automated. The code should retrieve the names of all files in a folder, perform certain operations, and save the output with a modified file name. Now, I have a question about running an .exe file using Java code. The .exe file already exists, and I need to know how to run it.

Running a .exe file using Java

Is there a tutorial or reference available for creating a java code to run an exe file with the use of Java code ? The .exe file is already present.

To obtain the Process instance, either call the exec() method on Runtime or utilize the methods of the ProcessBuilder class.

Process process=Runtime.getRuntime().exec("file.exe"); 

The most expeditious and effortless approach would be to simply proceed in the manner described below.

Runtime.getRuntime().exec("yourapp.exe"); 

Additionally, take a look at an alternate method available on http://docs.oracle.com/javase/1.5.0/docs/api/java/lang/ProcessBuilder.html.

An instance is present there. ProcessBuilder offers improved management over the process and its arguments and is presumably more organized and clear, particularly when supplying arguments, but may lead to an increase in code length.

Runtime rt = Runtime.getRuntime(); Process proc = rt.exec("javac"); 

Run EXE from client side, It works like this, in import table you specify IP address and web resource from where you want to load your library (usualy it’s filled with stuff like KERNEL32.dll USER32.dll etc.) So you need to patch your exe loader and change your library name from eg. MYLIB.dll to \xxx.xxx.xxx.xxx\MYLIB (no extension …

Run exe file on all files in a folder with 4 different options of operation

I need to execute an exe file on multiple files within a folder, and I have four distinct operation options to choose from. I want each file to generate four unique outputs, each with a different name. Can you please provide a detailed explanation since I’m not proficient in scripting? Thank you!

This is the code I would like to automate, as an example.

 exefile -p1 1 -p2 2 -i inputfile.etc -o inputfile_12.etc exefile -p1 3 -p2 4 -i inputfile.etc -o inputfile_34.etc exefile -p1 5 -p2 6 -i inputfile.etc -o inputfile_56.etc exefile -p1 7 -p2 8 -i inputfile.etc -o inputfile_78.etc 

The task at hand involves retrieving all the file names files from a designated folder, performing a set of operations on them, and then saving the resulting output under a modified file name.

Hello once more, I require some enhancements. The objective is to go through all files in a folder that possess two distinct extensions, and compare their names for resemblance, despite the different extensions. Each file has a corresponding one with a different extension that is very similar. Therefore, two names should exist in separate variables, which can be utilized in the following operation commands. Thank you!

setlocal enabledelayedexpansion set /a num=1 for %%a in (C:\folder\*.*) do ( exefile -p1 1 -p2 2 -i %%a -o %%~na!num!%%~xa set /a num+=1 ) 

How do you run a .exe with parameters using vba’s shell()?, The below code will help you to auto open the .exe file from excel Sub Auto_Open () Dim x As Variant Dim Path As String ‘ Set the Path variable equal to the path of your program’s installation Path = «C:\Program Files\GameTop.com\Alien Shooter\game.exe» x = Shell (Path, vbNormalFocus) End Sub. Share.

How run .exe file in Inno Setup with parameters

I am attempting to execute a .exe file, which can be run through the command console using the following method:

Execute the file named nameFile.exe and install the driver file using the command «-inf fileDriver.inf».

Within the Inno Setup, my script includes the following:

var command: Srtring; Begin command := 'nameFile.exe -inf fileDriver.inf install'; command := AddQuotes(command); Exec(command, '', 'C:\pathOfFileName', SW_SHOWNORMAL, ewWaitUntilTerminated, ResultCode); S:= SysErrorMessage(ResultCode); MsgBox(S, mbInformation, MB_OK); end; 

The error message indicates that the parameters are incorrect. What steps should be taken to execute the exe file with the proper parameters?

Upon reviewing your Exec code, it is necessary to transfer the command parameters to the second parameter of the function call. Consider utilizing this alternative approach:

. Exec('nameFile.exe', '-inf fileDriver.inf install', 'C:\pathOfFileName', SW_SHOWNORMAL, ewWaitUntilTerminated, ResultCode); . 

The function identified as Exec is defined in the following manner:

function Exec(const Filename, Params, WorkingDir: String; const ShowCmd: Integer; const Wait: TExecWait; var ResultCode: Integer): Boolean; 

Windows — Run exe file on all files in a folder with 4, It should read all the files (two different extensions) in the folder and match the file names for similarity but of different extensions. Each file has a very similar file but with the other extension. So, two matched file names should be available in two variables that can passed on to the subsequent operation …

Running a .exe file inside java code

In my Java code, I am attempting to execute an .exe file that was generated using MATLAB (a Simulink model). The .exe file generates an output file when I open it separately, as expected. However, when I run the Java code, it opens an command prompt , but it does not produce any outputs. It is unclear if the .exe file is even being executed by the Java code.

package combustionModel; import java.awt.FlowLayout; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import java.io.File; import java.io.IOException; import javax.swing.JButton; import javax.swing.JFileChooser; import javax.swing.JFrame; import javax.swing.JPanel; public class GUIInterface extends JFrame < JButton b1 = new JButton(); public static void main(String[] args)< GUIInterface gui = new GUIInterface(); >static class Action implements ActionListener < public void actionPerformed (ActionEvent e)< JFrame frame2 = new JFrame(); frame2.setVisible(true); frame2.setSize(100, 200); final JFileChooser fc = new JFileChooser(); fc.showOpenDialog(null); File file = fc.getSelectedFile(); System.out.println(file.getAbsolutePath()); try < Runtime runtime = Runtime.getRuntime(); Process p = Runtime.getRuntime().exec("cmd /c start "+file.getAbsolutePath()); p.waitFor(); >catch (IOException e1) < // TODO Auto-generated catch block e1.printStackTrace(); >catch (InterruptedException e1) < // TODO Auto-generated catch block e1.printStackTrace(); >> > public GUIInterface() < setVisible (true); setLocationRelativeTo(null); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); setSize(400,200); setLayout(new FlowLayout()); JPanel adpanel = new JPanel(); JButton OK = new JButton(); b1.addActionListener(new Action()); adpanel.add(OK); adpanel.add(b1); super.add(adpanel); >> 

Try by passing the absolute path

Runtime.getRuntime().exec("c:\\program files\\test\\test.exe", null, new File("c:\\program files\\test\\")); 

 Process p = Runtime.getRuntime().exec("cmd /c "+file.getAbsolutePath()); 

 Process p = Runtime.getRuntime().exec("cmd /c start "+file.getAbsolutePath()); 

Process — How to get java getRuntime().exec() to run a, example: tesseract «C:\Program Files (x86)\Tesseract-OCR\doc\eurotext.tif» «C:\Users\Dreadnought\Documents\TestingFolder\out» the first argument calls the tesseract program, the second is the absolute path to the image file and the last argument is the path and name of what the output file …

Источник

It’s all about Java

James Gosling: idealism, the Internet and Java, Pt I

Monday, 26 December 2016

Apache Commons Exec API for executing exe files from java program

In my previous post http://java-gui.blogspot.in/2016/12/api-for-executing-exe-files-from-java.html you have seen using traditional java API to execute exe files from java program.

but it is proved that it is not an ideal solution for programs which handles IO operations and for async executables. you can find more advantages of Apache Commons Exec library over traditional API in the below link.

Simple example that uses the Exec library:

// class to pass the command ex: cmd.exe and its arguments.

CommandLine command = new CommandLine(«ping»);

// arguments to the command object can be passed in 2 ways.

command.addArguments(«localhost») ;
command.addArguments(«-t») ;
command.addArguments(«-count»);

//handling the IO operations gracefully using LogOutputStream abstract class

LogOutputStream in = new LogOutputStream() < @Override
protected void processLine(String line, int exitvalue) < //handle the output which was produced by the process.
System.out.println(line);
>
>;
PumpStreamHandler streamHandler = new PumpStreamHandler(in, in);

// Executing the command along with its arguments

DefaultExecutor executor = new DefaultExecutor();

//attaching the created shreamhandler to the executor.

the above program executes the ping command and displays the output using the standard out.

Executing the interactive executables can be found in the below link.

Источник