A Title

Getting address bar contents with PHP

How do I get the contents of the browser address bar with PHP — assuming it
is possible?

In javascript it is done with: unescape(window.location.pathname), but is
there a php equivalent?

would SERVER[‘PHP_SELF’] do the job?

How do I get the contents of the browser address bar with PHP — assuming it
is possible?

In javascript it is done with: unescape(window.location.pathname), but is
there a php equivalent?

#v+
$fulluri = ‘http://’ . $_SERVER[‘SERVER_NAME’] . $_SERVER[‘REQUEST_URI’];
echo $fulluri;
?>
#v-

No
$_SERVER[‘SERVER_NAME’].$_SERVER[‘REQUEST_URI’] should be prefered.

$_SERVER[‘HTTP_HOST’] is better actually, as it gives you the port number as
well.

Uzytkownik «Jedi121» napisal w wiadomosci
news:me********************************@free.fr.Re movethis. Matthew Robinson a �crit le 21/01/2004 :

No
$_SERVER[‘SERVER_NAME’].$_SERVER[‘REQUEST_URI’] should be prefered.

«Chung Leong» wrote in message
news:k6********************@comcast.com. $_SERVER[‘HTTP_HOST’] is better actually, as it gives you the port number as well.

Uzytkownik «Jedi121» napisal w wiadomosci
news:me********************************@free.fr.Re movethis. Matthew Robinson a �crit le 21/01/2004 :

No
$_SERVER[‘SERVER_NAME’].$_SERVER[‘REQUEST_URI’] should be prefered.

It wouldn’t work in a frameset though. Least not that I could see.

$_SERVER[‘REQUEST_URI’] is rteturning nothing here. Any idea why that might
be?

«Pedro Graca» wrote in message
news:bu************@ID-203069.news.uni-berlin.de.

Spidah wrote: How do I get the contents of the browser address bar with PHP — assuming it is possible?

In javascript it is done with: unescape(window.location.pathname), but is there a php equivalent?

#v+
$fulluri = ‘http://’ . $_SERVER[‘SERVER_NAME’] . $_SERVER[‘REQUEST_URI’];
echo $fulluri;
?>
#v-

I have however managed to get what I need with:

$temp = «http://» .
$_SERVER[‘SERVER_NAME’].»/».$_SERVER[‘PHP_SELF’].»?».$_SERVER[‘QUERY_STRING’
];
echo $temp;

$_SERVER[‘REQUEST_URI’] is rteturning nothing here. Any idea why that might be?

«Pedro Graca» wrote in message
news:bu************@ID-203069.news.uni-berlin.de. Spidah wrote: How do I get the contents of the browser address bar with PHP —

In javascript it is done with: unescape(window.location.pathname), but is there a php equivalent?

#v+
$fulluri = ‘http://’ . $_SERVER[‘SERVER_NAME’] . $_SERVER[‘REQUEST_URI’]; echo $fulluri;
?>
#v-

«Chung Leong» wrote in message
news:k6********************@comcast.com. $_SERVER[‘HTTP_HOST’] is better actually, as it gives you the port number

Uzytkownik «Jedi121» napisal w wiadomosci
news:me********************************@free.fr.Re movethis. > Matthew Robinson a �crit le 21/01/2004 :
> > would SERVER[‘PHP_SELF’] do the job?
>
> No
> $_SERVER[‘SERVER_NAME’].$_SERVER[‘REQUEST_URI’] should be prefered.
>
>

It wouldn’t work in a frameset though. Least not that I could see.

Or if the URL contained a fragment identifier:
http://www.example.com/foo.php#bar

Regarding this well-known quote, often attributed to Chris Mosser’s famous
«Tue, 20 Jan 2004 16:40:42 -0800» speech:

«Chung Leong» wrote in message
news:k6********************@comcast.com. $_SERVER[‘HTTP_HOST’] is better actually, as it gives you the port number

Uzytkownik «Jedi121» napisal w wiadomosci
news:me********************************@free.fr.Re movethis. Matthew Robinson a �crit le 21/01/2004 :
> would SERVER[‘PHP_SELF’] do the job?

No
$_SERVER[‘SERVER_NAME’].$_SERVER[‘REQUEST_URI’] should be prefered.

It wouldn’t work in a frameset though. Least not that I could see.

Framesets are totally client-side. You’d have to use JavaScript to pass the
value to PHP, then.

I have a file called index.php which is the default file served.
$_SERVER[‘PHP_SELF’] would return ‘/index.php’ while
$_SERVER[‘REQUEST_URI’] would return ‘/’.

Also, if I am using something like mod_rewrite PHP_SELF is completely
different to REQUEST_URI.

Since the original poster said they wanted the contents of the URI bar
they should be using REQUEST_URI rather than PHP_SELF. 🙂

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if statement based on the address bar ?

I’m not sure if you know this already but just in case you dont.

To get the variable in the address bar into the page i.e., page use $page=$_GET[‘page’] This for your first example would return $page=21. Based on the variables you can echo what you need.

Similarly …

You should then be able to elseif for the other values.

$pg = $_GET['page']; if($pg==21) < echo 'Test. '; >else if ($pg==22)

Please encapsulate your string literals in quotes. else if ($pg==»21;n=’.$get_numbers.'») < echo 'Numbers. '; >The direct entry for the 21 is because of the integer. You need to encase the string in quotes to do the check.

All 14 Replies

I’m not sure if you know this already but just in case you dont. To get the variable in the address bar into the page i.e., page use $page=$_GET[‘page’] This for your first example would return $page=21. Based on the variables you can echo what you need. Similarly for the rest.

I’m not sure if you know this already but just in case you dont. To get the variable in the address bar into the page i.e., page use $page=$_GET[‘page’] This for your first example would return $page=21. Based on the variables you can echo what you need. Similarly for the rest.

I tried something like that using the below but because of the way the URL’s are it would only let me use 21 and nothing else.

 $pg = (int) $_GET[ 'page' ]; if( 21 === $pg )

$pg = $_GET['page']; if($pg==21) < echo 'Test. '; >else if ($pg==22)

$pg = $_GET['page']; if($pg==21) < echo 'Test. '; >else if ($pg==22)

Because of the special characters in my link it doesnt appear to want to work, thats what I guess I was trying t osay before. $pg = $_GET;
if($pg==21) < echo 'Regular. ';>
else if ($pg==21;n=’.$get_numbers.’) < echo 'Numbers. '; >
else if ($pg==21;l=’.$get_letters.’) < echo 'Letters. '; >Gives me this: syntax error, unexpected ‘;’

Please encapsulate your string literals in quotes. else if ($pg==»21;n=’.$get_numbers.'») < echo 'Numbers. '; >The direct entry for the 21 is because of the integer. You need to encase the string in quotes to do the check.

In your code $get_numbers and $get_letters are variables.
In the urls in the link you are building you are using the value of those variables in the url. So,

$page = (int) $_GET['page']; $letter = $_GET['l']; $numbers = $_GET['n'];

Please encapsulate your string literals in quotes. else if ($pg==»21;n=’.$get_numbers.'») < echo 'Numbers. '; >The direct entry for the 21 is because of the integer. You need to encase the string in quotes to do the check.

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get url in php from address bar – How to get the URL shown at address bar?

get url in php from address bar using a combination of $_SERVER[“HTTP_HOST”] and $_SERVER[“REQUEST_URI”] Example.

get url in php from address bar

i need to use predefined variable $_SERVER. It is an array containing details such as headers, paths, as well as script locations.

Useful Environment variables of URL:

• $_SERVER[‘HTTP_HOST’] = Host name from the current request.
• $_SERVER[‘HTTP’] = Set to a non-empty value if the protocol is HTTP
• $_SERVER[‘HTTPS’] = Set to a non-empty value if the protocol is HTTPS
• $_SERVER[‘SERVER_PORT’] = Server port. Default is: 80
• $_SERVER[‘REQUEST_URI’] = The URI to access this page,For example, ‘/index.php’.

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function get_live_active_path() < $get_live_active_path = (@$_SERVER["HTTPS"] == "on") ? "https://" : "http://"; $get_live_active_path .= $_SERVER["SERVER_NAME"]; if($_SERVER["SERVER_PORT"] != "80" && $_SERVER["SERVER_PORT"] != "443") < $get_live_active_path .= ":".$_SERVER["SERVER_PORT"]; >$get_live_active_path .= $_SERVER["REQUEST_URI"]; return $get_live_active_path; >

In PHP, you can retrieve the complete URL from the address bar using the $_SERVER[‘REQUEST_URI’] superglobal variable. Here is an example of how to use it:

$url = "http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI']; echo $url;

In this example, we first concatenate the “http://” protocol with the $_SERVER[‘HTTP_HOST’] server name, and then append the $_SERVER[‘REQUEST_URI’] path and query string to get the complete URL. The $_SERVER[‘HTTP_HOST’] variable contains the domain name or IP address of the server, and the $_SERVER[‘REQUEST_URI’] variable contains the path and query string of the current request.

Note that this method only works if the request was made using the HTTP or HTTPS protocol. If the request was made using a different protocol, such as FTP or SSH, the $_SERVER[‘HTTP_HOST’] variable may not be set, and you may need to use a different method to retrieve the complete URL.

I hope you get an idea about get url in php from address bar.
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